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iVinArrow [24]
3 years ago
14

Y’all this assignment determines if i pass , please help me out.. Part 2: Graphing the Effect of Changing Mass and Velocity on K

inetic Energy.

Physics
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:

* energy is proportional to masses. in a graph it would look like a line

* kinetic energy varies with the square of the velocity, In a graph it gives rise to a quadratic curve

Explanation:

Kinetic energy is defined by

        K = ½ m v²

when analyzing this expression we can see:

* energy is proportional to masses. Therefore, doubling the mass doubles the kinetic energy and if the mass rises 4 times the energy rises 4 times, that is, they are directly proportional, in a graph it would look like a line

* kinetic energy varies with the square of the velocity. Therefore by doubling the speed the energy goes up 4 times. In a graph it gives rise to a quadratic curve

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The wavelength would be 410 m/s
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In the chemical formula 3NH4, how many total atoms of nitrogen (N
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True

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A 1300 kg car starts at rest and rolls down a hill from a height of 10.0 m. It then moves across a
Makovka662 [10]

Answer:

0.51 m

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Kinetic energy, KE=½kx²

Where k is spring constant and x is the compression of spring

Potential energy, PE=mgh

Where g is acceleration due to gravity, h is height and m is mass

Equating KE=PE

mgh=½kx²

Making x the subject of formula

x=\sqrt {\frac {2mgh}{k}}

Substituting 9.81 m/s² for g, 1300 kg for m, 10m for h and 1000000 for k then

x=\sqrt \frac {2*1300*9.81*10}{1000000}=0.50503465227646m\\x\approx 0.51 m

5 0
3 years ago
A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal fri
zhannawk [14.2K]

Answer:

The speed of the knife after passing through the target is 9.33 m/s.

Explanation:

We can find the speed of the knife after the impact by conservation of linear momentum:

p_{i} = p_{f}

m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}}

Where:

m_{k}: is the mass of the knife = 22.5 g = 0.0225 kg

m_{t}: is the mass of the target = 300 g = 0.300 kg

v_{i_{k}}: is the initial speed of the knife = 40.0 m/s

v_{i_{t}}: is the initial speed of the target = 2.30 m/s

v_{f_{k}}: is the final speed of the knife =?

v_{f_{t}}: is the final speed of the target = 0 (it is stopped)

Taking as a positive direction the direction of the knife movement, we have:

m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}}  

v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s

Therefore, the speed of the knife after passing through the target is 9.33 m/s.

I hope it helps you!              

4 0
3 years ago
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