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Sedaia [141]
2 years ago
13

How big is earth and what is its distance from and towards earth

Physics
1 answer:
ss7ja [257]2 years ago
8 0

Answer:

Using those measurements, the equatorial circumference of Earth is about 24,901 miles (40,075 km). However, from pole to pole — the meridional circumference — Earth is only 24,860 miles (40,008 km) around.

Explanation:

hoped it helped!!

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A 0.250 kgkg toy is undergoing SHM on the end of a horizontal spring with force constant 300 N/mN/m. When the toy is 0.0120 mm f
konstantin123 [22]

Answer:

(a) The total energy of the object at any point in its motion is 0.0416 J

(b) The amplitude of the motion is 0.0167 m

(c) The maximum speed attained by the object during its motion is 0.577 m/s

Explanation:

Given;

mass of the toy, m = 0.25 kg

force constant of the spring, k = 300 N/m

displacement of the toy, x = 0.012 m

speed of the toy, v = 0.4 m/s

(a) The total energy of the object at any point in its motion

E = ¹/₂mv² + ¹/₂kx²

E = ¹/₂ (0.25)(0.4)² + ¹/₂ (300)(0.012)²

E = 0.0416 J

(b) the amplitude of the motion

E = ¹/₂KA²

A = \sqrt{\frac{2E}{K} } \\\\A = \sqrt{\frac{2*0.0416}{300} } \\\\A = 0.0167 \ m

(c) the maximum speed attained by the object during its motion

E = \frac{1}{2} mv_{max}^2\\\\v_{max} = \sqrt{\frac{2E}{m} } \\\\v_{max} = \sqrt{\frac{2*0.0416}{0.25} } \\\\v_{max} = 0.577 \ m/s

8 0
3 years ago
Assertion : Human ear converts vibration with audible frequencies into electric signals. Reason : Audible sound lies in the rang
joja [24]
A I took I the test and r is the secondary
4 0
2 years ago
A train traveling at 27.5 accelerates to 42.4 m s over 75.0 s What is the displacement of the train in this time period A train
jarptica [38.1K]

Answer:

The displacement of the train in this time period is 2,616.86 m.

Explanation:

A Uniformly Varied Rectilinear Motion is Rectilinear because the mobile moves in a straight line, Uniformly because of there is a magnitude that remains constant (in this case the acceleration) and Varied because the speed varies, the final speed being different from the initial one.

In other words, a motion is uniformly varied rectilinear when the trajectory of the mobile is a straight line and its speed varies the same amount in each unit of time (the speed is constant and the acceleration is variable).

An independent equation of useful time in this type of movement is:

vf^{2} =vi^{2} +2*a*d <em>Expression A</em>

where:

  • vf = final velocity
  • vi = initial velocity
  • a = acceleration
  • d = distance

The equation of velocity as a function of time in this type of movement is:

vf=vi + a*t

So the velocity can be calculated as: a=\frac{vf-vi}{t}

In this case:

  • vf=42.4 m/s
  • vi=27.5 m/s
  • t=75 s

Replacing in the definition of acceleration:  a=\frac{42.4 m/s-27.5 m/s}{75 s}

a=0.199 m/s²

Now, replacing in expression A:

(42.4 m/s)^{2} =(27.5 m/s)^{2} +2*(0.199 m/s^{2}) *d

Solving:

d= \frac{(42.4 m/s)^{2} - (27.5 m/s)^{2} }{2*(0.199 m/s^{2}) }

d= 2,616.86 m

<u><em>The displacement of the train in this time period is 2,616.86 m.</em></u>

4 0
3 years ago
At a country music festival, a band is playing at the end of a crowded
Dominik [7]

Answer:

2270 full wavelengths.

Explanation:

The wavelength \lambda of the sound wave (assuming sound speed of  v= 343m/s) is

\lambda = \dfrac{v}{f} = \dfrac{343m/s}{400hz}

\lambda = 0.8575m.

Now, assuming the distance to the last row is 1947m, the number n of wavelengths that fit into this distance are

n = \dfrac{1947m}{0.8575m}

n= 2270.55

which is 2270 full wavelengths.

Hence, there are 2270 full wavelengths between the stage and the last row of the crowd.

7 0
3 years ago
A pure substance can be a
valina [46]
Hey there! A pure substance can be a element.

Hope this helps! :)
4 0
4 years ago
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