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S_A_V [24]
2 years ago
8

What other ideas could have been influenced by plato’s cave.

Physics
1 answer:
fiasKO [112]2 years ago
7 0

Answer:

The story he tells about the cave could have influenced different modern day ideas. Some examples might include religion, abuse, and imprisonment.

Explanation: :)

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If a book has a a mass of 2 kg, how much does the book weigh?
Anestetic [448]

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A. 20 N

Explanation:

the weight of book is 2×10= 20N

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Which option describes nonmetals?
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A golfer imparts a speed of 30.3 m/s to a ball, and it travels the maximum possible distance before landing on the green. the te
sergey [27]

<u>Answer:</u>

a) Time spend by ball in air = 4.368 seconds

b)   Longest hole that golfer can make = 93.59 meter

<u>Explanation:</u>

  Projectile motion has two types of motion Horizontal and Vertical motion.

Vertical motion:

         We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

         Considering upward vertical motion of projectile.

         In this case, Initial velocity = vertical component of velocity = u sin θ, acceleration = acceleration due to gravity = -g m/s^2 and final velocity = 0 m/s.

        0 = u sin θ - gt

         t = u sin θ/g

    Total time for vertical motion is two times time taken for upward vertical motion of projectile.

    So total travel time of projectile = 2u sin θ/g

Horizontal motion:

  We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

  In this case Initial velocity = horizontal component of velocity = u cos θ, acceleration = 0 m/s^2 and time taken = 2u sin θ /g

 So range of projectile,  R=ucos\theta*\frac{2u sin\theta}{g} = \frac{u^2sin2\theta}{g}

a) We have golf ball travels maximum distance, so range is maximum.

                 Maximum range is when, sin 2θ =1

                             =>  θ = 45⁰

    Now we have travel time of projectile, t =  2u sin θ/g  

          Initial velocity = 30.3 m/s and  θ = 45⁰

                     So time spend in air, t = \frac{2*30.3*sin45}{9.81} =4.368 seconds

 b) Longest hole that golfer can make = Range of projectile = \frac{u^2sin2\theta}{g}

      Longest hole that golfer can make = \frac{30.3^2sin(2*45)}{9.81}=93.59 meter

4 0
3 years ago
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