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ehidna [41]
1 year ago
9

The equation a = 50m + 100 represents the amount of money in Malorie’s bank account as a function of time, in months. The table

shows the amount in Katina’s bank account for a period of several months.
Month 0 1 2 3 4 5
Katina's Bank Account 200 220 240 260 280 300

A. How much money is in Malorie’s bank account when Katina has $280 in her account? Show your work.

B. Whose account changes at a greater rate? Show your work.
Mathematics
1 answer:
Gnesinka [82]1 year ago
3 0

Answer:

A: 300 B: Malorie

Step-by-step explanation: Katina's account starts at $200 and increases by $20 each month. Malorie starts at only $100 but increases at a rate of $50 per month. for "A", Katina is 4 months in which equals $280. so, you take Malorie's $50 rate times the 4 months and you get $200. You then add that $200 to the starting $100 to equal $300.

B: 50m>20m. Malorie's monthly rate is listed in the equation as $50. Katina's rate of $20 comes from the $20 increase in her account each month.

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-3y/5

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3/5y+(-6/5y)=

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3 years ago
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21 degrees

Step-by-step explanation:

Triangles have a total angle of 180 degrees.

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3x+3+4x+135=180

Subtract 135 from both sides and combine like terms

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Divide both sides by 7

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7 0
2 years ago
Evaluate the expression<br> cos(30°)=
alina1380 [7]

Answer:

cos (30) =\sqrt{\frac{3}{2} } =0.8660

Step-by-step explanation:

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cos(30°) = √1 – sin230°

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cos(30°) = √1 – (1/2)2

cos(30°) = √1 – (1/4)

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3 0
1 year ago
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A hypothesis test is conducted at the .05 level of significance to test whether or not the population correlation is zero. If th
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The test statistics for Pearson correlation coefficient is thus computed as :

t =\dfrac{r \sqrt{(n-2)}} { \sqrt{(1-(r)^2)} }

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t =\dfrac{0.60 \sqrt{(25-2)}} { \sqrt{(1-(0.60)^2)} }

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Since computed value of t is greater than the critical value of t; We reject the null hypothesis and accept the alternative hypothesis.

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6 0
3 years ago
What is this answer?
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