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alina1380 [7]
3 years ago
11

Do compounds have the same properties as the elements that make them up?

Chemistry
1 answer:
WITCHER [35]3 years ago
7 0
No, because when elements are chemically combined their properties change

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The alliance to save energy seeks to increase energy efficiency through _______. a. petitioning consumers to change their habits
TEA [102]

The alliance to save energy seeks to increase energy efficiency through: b. lobbying for policy changes.

<h3> Who is a lobbyist?</h3>

A lobbyist can be defined as an activist whose endeavor and intent is to persuade government officials to enact laws and policies (legislation) that would significantly benefit their group at large.

This ultimately implies that, the alliance to save energy seeks to increase energy efficiency through lobbying for policy changes by gaining access to legislative and executive arms of government, in a bid to influence their thought process.

Read more on lobbying here: brainly.com/question/16577797

#SPJ4

6 0
2 years ago
A liquid that occupies a volume of 8.2 L has a mass of 5.6 kg ehat is the density of the liquid in kg/l
BaLLatris [955]
Hey there!

Mass = 5.6 Kg

Volume =8.2 L

D = m / V

D = 5.6 / 8.2

D = 0.6829 Kg/L

hope this helps!
4 0
3 years ago
Read 2 more answers
The model below represents a nuclear reaction. Atom 1 is present before the reaction and Atom 2 and Atom 3 are produced after th
NemiM [27]
Option C. Does not produce energy in the sun. Because energy in the sun is produced by fusion; this is the combination of two atoms, and that is the opposite to what the model shows.
3 0
3 years ago
Read 2 more answers
Calculate the amount of heat, in kilojoules, required to turn solid ammonia at -78 degrees Celsius to gaseous ammonia at standar
zhuklara [117]

Answer:

132

Explanation:

3 0
4 years ago
A 40 g gold coin is cooled from 50°C to 10°C (CAu is 0.13 J/g-°
Debora [2.8K]
When the Heat gain or lose = the mass * specific heat * ΔT

and when we have the mass of gold coin= 40 g 

and the specific Heat of gold=  0.13 J/g°

and ΔT = (Tf- Ti) = 10°C - 50°C = -40 °C

so by substitution:

∴Heat H = 40 g * 0.13 J/g° * -40
               = - 208 J
4 0
3 years ago
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