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bearhunter [10]
3 years ago
8

A 40 g gold coin is cooled from 50°C to 10°C (CAu is 0.13 J/g-°

Chemistry
1 answer:
Debora [2.8K]3 years ago
4 0
When the Heat gain or lose = the mass * specific heat * ΔT

and when we have the mass of gold coin= 40 g 

and the specific Heat of gold=  0.13 J/g°

and ΔT = (Tf- Ti) = 10°C - 50°C = -40 °C

so by substitution:

∴Heat H = 40 g * 0.13 J/g° * -40
               = - 208 J
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Which orbital is partially filled in the Zirconium (ZI) atom?
Nikolay [14]

Answer:

4d orbital.

Explanation:

Hello!

In this case, since zirconium's atomic number is 40, we fill in the electron configuration up to 40 as shown below:

1s^2,2s^2,2p^6, 3s^2,3p^6,4s^2,3d^{10},4p^6,5s^2,4d^2

Thus, the orbital 4d is partially filled.

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3 years ago
Find the linear function Cequals​f(F) that gives the reading on the Celsius temperature scale corresponding to a reading on the
padilas [110]

Answer:

C = (5/9) F - (160/9)

They both read equal at Z = - 40

Explanation:

We are looking for a linear function so we can write the following condition

Y = aX + b

Applying it to the exercise we got C = a F + b

Let's use the facts that C = 0 when F = 32 and C = 100 when F = 212

0 = 32 a + b            (1)

100 = 212 a + b       (2)

From (1) b = - 32 a , when we replace this in (2) we obtain a = (5/9)

and b = - (5/9)32 = - 160/9

Finally the linear function is C = (5/9) F - (160/9)

Both readings are equal at a Z number so

Z = (5/9) Z - 160/9

(4/9) Z = -160/9 and Z = - 40

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Answer:

Prejudice

Explanation:

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3 years ago
How many grams hydrogen in 4.5 mol H2SO4
swat32
H2SO4 ---> 2H^+ + SO4^2-

Hence n H+ = 9 mols

Mass of H = nM = (9*1) = 9g


Alternately

mass of H2SO4= nM= 4.5*98= 441

Mass of H= mass h2so4 * molar mass of H/molar mass of h2so4
Mass of H= 441 * 2/98 = 9g

4 0
3 years ago
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