Protozoa is known as ring worm
Answer:
The answer to your question is 8,32 L
Explanation:
Data
Pressure 1 = 104.5 kPa
Volume 1 = 3.4 L
Pressure 2 = 42.7 kPa
Volume 2 = ?
Formula
- To solve this problem use the Boyle's law.
P1V1 = P2V2
- Solve for V2
V2 = P1V1 / P2
- Substitution
V2 = (104.5)(3.4) / 42.7
-Simplification
V2 = 355.3 / 42.7
- Result
V2 = 8.32 L
when the thermal energy is the energy contained within a system that is responsible for its temperature.
and when the thermal energy is can be determined by this formula:
q = M * C *ΔT
when q is the thermal energy
and M is the mass of water = 100 g
and C is the specific heat capacity of water = 4.18 joules/gram.°C
and T is the difference in Temperature = 50 °C
So by substitution:
∴ q = 100 g * 4.18 J/g.°C * 50
= 20900 J = 20.9 KJ
A solution (in this experiment solution of NaNO₃) freezes at a lower temperature than does the pure solvent (deionized water). The higher the
solute concentration (sodium nitrate), freezing point depression of the solution will be greater.
Equation describing the change in freezing point:
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b - molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
First measure freezing point of pure solvent (deionized water). Than make solutions of NaNO₃ with different molality and measure separately their freezing points. Use equation to calculate Kf.
Im pretty sure its A funding because thats alot of money
