Answer:
Explanation:
Given
speed of ball 
launch angle 
Range of a Projectile 
Range will be common for two angles i.e. ![\theta [tex] and [tex]90-\theta](https://tex.z-dn.net/?f=%5Ctheta%20%5Btex%5D%20and%20%5Btex%5D90-%5Ctheta%20)
for 

For 



Answer:
<em>The correct option is 1. 720 m</em>
Explanation:
<u>Projectile Motion</u>
When an object is launched in free air (no friction) with an initial speed vo at an angle
, it describes a curve which has two components: one in the horizontal direction and the other in the vertical direction. The data provided gives us the initial conditions of the survival package's launch.


The initial velocity has these components in the x and y coordinates respectively:


And we know the plane has an altitude of 600 m, so the package will reach ground level when:

The vertical distance traveled is given by:

We'll set up an equation to find the time when the package lands


Solving for t, we find only one positive solution:

The horizontal distance is:

The correct option is 1. 720 m
Answer:6m/s^2
Explanation:
Mass =3kg
Force=18N
Acceleration =force ➗ mass
Acceleration =18 ➗ 3
Acceleration =6
Acceleration =6m/s^2
False it will not affect your grade
The answer is false
Thats my far estimation