Answer:
a = 0.3 m/s²
Explanation:
Given: 45 N, 150 kg
To find: a
Formula: 
Solution: To find a, divide the force by the weight
A = F ÷ m
= 45 ÷ 150
= 0.3 m/s²
Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.
Answer:
the magnitude of the force that one particle exerts on the other is 79.08 N
Explanation:
given information:
q₁ = 3.77 μC = -3.77 x 10⁻⁶ C
q₂ = 4.39 μC = 4.39 x 10⁻⁶ C
r = 4.34 cm = 4.34 x 10⁻² m
What is the magnitude of the force that one particle exerts on the other?
lFl = kq₁q₂/r²
= (9 x 10⁹) (3.77 x 10⁻⁶) (4.39 x 10⁻⁶)/(4.34 x 10⁻²)²
= 79.08 N
i think it would be newton's first law of motion
Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.
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For energy released from vaporisation,
Q(Energy) = m(mass of vapour) X l (latent heat of vaporisation)
= (0.65) X (2257)