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3 years ago

10

How is the centripetal force related to the tangential velocity of the mass?.

1 answer:

frosja888 [35]3 years ago

3 0

Answer:

The force is proportional to the square of the tangential velocity of the mass. How many different masses are we going to perform this experiment with?

Explanation:

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Afina-wow [57]

Water does not have a pH of 0, its actually 7. Also, it is not less dense than ice. Lastly, it does not dissolve in most substances, its the complete opposite. As its a solvent, not a solute.

Answer: B

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3 years ago

A simple pendulum with length L is swinging freely with

Trava [24]

Answer:

it will be 1/√2 of its original period.

Explanation:

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3 years ago

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at rrr = 4.0 mm is πr

max2010maxim [7]

Complete Question

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at r_1 = 4.0 mm is π rad. At that instant, what is the phase at r_2 = 3.5 mm ? Express your answer to two significant figures and include the appropriate units.

Answer:

The phase at the second point is $\phi _2 = 1.57 \ rad$

Explanation:

From the question we are told that

The wavelength of the spherical wave is $\lambda = 2.0 \ mm = \frac{2}{1000} = 0.002 \ m$

The first radius is $r_1 = 4.0 \ mm = \frac{4}{1000} = 0.004 \ m$

The phase at that instant is $\phi _1 = \pi \ rad$

The second radius is $r_2 = 3.5 \ mm = \frac{3.5}{1000} = 0.0035 \ m$

Generally the phase difference is mathematically represented as

$\Delta \phi = \phi _2 - \phi _1$

this can also be expressed as

$\Delta \phi = \frac{2 \pi }{\lambda } (r_2 - r_1 )$

So we have that

$\phi _2 - \phi _1 = \frac{2 \pi }{\lambda } (r_2 - r_1 )$

substituting values

$\phi _2 - \pi = \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 )$

$\phi _2 = \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 ) + 3.142$

$\phi _2 = 1.57 \ rad$

7 0

3 years ago

Zina [86]

Answer:

The current through the wire is equal to 0.8 A.

Explanation:

Given that,

The length of a copper wire = 2 m

Potential difference = 24 mV

The current through the wire is 0.40 A.

The new potential difference is 48 mV.

We need to find the current through the wire.

As the potential difference is doubled for second wire. So the new current will be :

I' = 2I

= 2 × 0.4

= 0.80 A

So, the current through the wire is equal to 0.8 A.

5 0

3 years ago

A copper sphere was moving at 25 m/s when it hit another object. This caused all of the KE to be converted into thermal energy f

Verdich [7]

Answer:

$\Delta T = 0.81 ^oC$

Explanation:

As we know by energy conservation

All its kinetic energy will convert into thermal energy to raise its temperature

$\frac{1}{2}mv^2 = ms\Delta T$

now divide both sides by mass of the object

$\frac{1}{2}v^2 = s\Delta T$

so change in temperature is given as

$\Delta T = \frac{v^2}{2s}$

$\Delta T = \frac{25^2}{2\times 387}$

$\Delta T = 0.81^oC$

3 0

3 years ago