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Julli [10]
3 years ago
12

A 4.00 kg block is pushed along the ceiling with a constant applied force of 85.0 N that acts at an angle of 55.0 degrees with t

he horizontal. The block accelerates to the right at 6.00 m/s2. Determine the coefficient of kinetic friction between block and ceiling.
Physics
1 answer:
steposvetlana [31]3 years ago
6 0

Answer:

0.35

Explanation:

According to Newton's second law;

\sum Fx = ma

Fm - Ff =ma

Fm is the moving force = Wsin theta

Fm = 4(9.8)sin55

Fm = 32.1N

Ff is the frictional force = nmgcos theta

Ff = n(4)(9.8)cos55

Ff = 22.48n

Acceleration a = 6.0m/s²

Substitute the given values into the formula and get the coefficient of friction

32.11-23.48n = 4(6)

32.11-24= 23.48n

8.11 = 23.48

n = 8.11/23.48

n = 0.35

Hence the coefficient of friction is 0.35

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For number one the answer is decrease.

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6 0
3 years ago
Read 2 more answers
List down all the jovian planets in order of increasing distance from the sun
Olenka [21]

Answer:

There are total eight planets in the solar system and the average distance from the sun to each planet in increasing order is given below.

Explanation:

The average distance from the sun is listed below in increasing order.

1. Mercury  - It is the most closet planet to Sun, 57 million km

2. Venus  - 108 million km

3. Earth  - 150 million km

4. Mars  - 228 million km

5. Jupiter  - 779 million km

6. Saturn  - 1.43 billion km

7. Uranus  - 2.88 billion km

8. Neptun - It is the most farthest from the Sun, 4.50 billion km

8 0
3 years ago
A 84-kg man stands on a bathroom scale inside an elevator. the scale measures in units of newtons. (a) the elevator accelerates
valentina_108 [34]

Answer:

  94 kg

Explanation:

The mass registered by the scale is based on the assumption that the force applied is due entirely to gravity. If the force is greater, then the indicated mass will be greater.

__

<h3>how many g's</h3>

As a fraction of the acceleration of gravity, the elevator's acceleration is ...

  (1.2 m/s²)/(9.8 m/s²) ≈ 6/49

<h3>net force</h3>

The force required to produce a given acceleration is found by the formula ...

  F = ma . . . . . . . force on mass m to produce acceleration 'a'

When the man is stationary on the scale, the upward force it supplies is balanced by the downward force on the man due to gravity. The force and the mass are proportional, and the constant of proportionality (the acceleration due to gravity) is used to calibrate the scale. More force is thus translated to a higher mass reading.

Since the man's net acceleration is upward at the rate of 6/49×g, the total force applied by the scale is (1 +6/49) = 55/49 times as great as when the man is stationary. This greater force gets translated to a greater mass reading.

The force is equivalent to what would be required to support a stationary man with a mass of ...

  (84 kg)(55/49) = 94 2/7 kg

The scale would read about 94 kg during the upward acceleration period.

3 0
2 years ago
The SI unit for acceleration is_____<br> a m/s.<br> b m/s 2<br> c m/s2<br> d none of the above
zalisa [80]
I dont know from option
Because SI Unit of acceleration is m/s^2
7 0
3 years ago
The cart now moves toward the right with an acceleration toward the right of 2.50 m/s2. What does spring scale Fz read? Show you
katrin2010 [14]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

The spring scale F_2 reads  F_2 =  2.4225 \ N

Explanation:

From the question we are told that

      The first force is  F_1  =  10.5 \ N

      The acceleration by which the cart moves to the right is  a = 2.50  \ m/s^2

      The mass of the cart is  m  = 3.231  kg

       

Generally the net force on the cart is  

       F_{net} = F_1 -  F_2

This net force is mathematically represented as

      F_{net} =  m * a

So  

        m*  a =  10 - F_2

        F_2 =  10.5 -  2.5 (3.231)

        F_2 =  2.4225 \ N

 

3 0
3 years ago
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