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yanalaym [24]
2 years ago
15

This her sisterrrrrrrrrrrrr

Physics
1 answer:
victus00 [196]2 years ago
3 0

Answer:

YEss this is her sister

Explanation: got a problem

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Ask Your Teacher A flight attendant pulls her 69 N flight bag a distance of 268 m along a level airport floor at a constant velo
Simora [160]

Answer:

a)  W = 5360 J  b)  μ = 0.29

Explanation:

a) The work is, bold indicate vectors

         W = F. d ​​= F d cos T

         W = 40 268 cos 60

         W = 5360 J

b) The force of friction and opposes the movement of the body and if the speed of the body is constant implies that the external force in the direction of the movement is equal to the force of friction, or which work is the same

         W_{fr} = -5360J

The negative sign is because the force of friction is contrary to the direction of movement

c) Let's write the work of the friction force

           W_{fr} = fr d cos 180

           fr = μ N

Since the body is on a horizontal surface, from Newton's second law on the Y axis

          N-W = 0

          N = W

          fr = μ W

         W_{fr} = - μ W d

         μ = - W_{fr} / W d

         μ = - (-5360) / 69 268

         μ = 0.29

7 0
3 years ago
At launch a rocket ship weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 s to reach 161 km/h; at the end
SpyIntel [72]

Answer:

5.590278\ m/s^2

7.74038461538\ m/s^2

178.888896 m

12790.56 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{161}{3.6}-0}{8}\\\Rightarrow a=5.590278\ m/s^2

The acceleration is 5.590278\ m/s^2

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{1610}{3.6}-\dfrac{161}{3.6}}{60-8}\\\Rightarrow a=7.74038461538\ m/s^2

The acceleration is 7.74038461538\ m/s^2

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 5.590278\times 8^2\\\Rightarrow s=178.888896\ m

Distance traveled in the first 8 seconds is 178.888896 m

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=\dfrac{161}{3.6}\times 52+\dfrac{1}{2}\times 7.74038461538\times 52^2\\\Rightarrow s=12790.56\ m

Distance traveled during 8-60 second interval is 12790.56 m

6 0
3 years ago
Why it is easier to remove a 2p electron from an oxygen atom than from a nitrogen atom?
DedPeter [7]

Answer:

The electrons in oxygen are paired while in nitrogen, they are not.

Explanation:

To analyse this we start with writing out the ground state electronic configurations for both elements.

Oxygen: 1s²2s²2p4 meaning the p subshell has the following arrangement of electrons                  ↑↓   ↑   ↑

Nitrogen : 1s²2s²2p³ meaning the p subshell has the following arrangement of electrons  ↑    ↑    ↑

Clearly the paired electron in oxygen will be experiencing repulsion from the electron it shares an orbital with causing it to be removed easily. The electrons in nitrogen are unpaired, each orbital is singly occupied

7 0
3 years ago
If you move two objects father Paul how does the force of gravity between the two objects change
Yanka [14]
The force of gravity gets stronger.

4 0
3 years ago
In Converging and Diverging lenses all real images are
AlladinOne [14]
B.......................
5 0
3 years ago
Read 2 more answers
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