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yanalaym [24]
2 years ago
15

This her sisterrrrrrrrrrrrr

Physics
1 answer:
victus00 [196]2 years ago
3 0

Answer:

YEss this is her sister

Explanation: got a problem

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The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart. The potential difference between the plates is 93
Kisachek [45]

Answer: a) E = 311,666.7 V/m, b) q = 1.54×10^-10c, c) F = 4.799×10^-5 N, d) 0.0629 J

Explanation:

Area = 700cm² = (700/100)² = 7² = 49m²

Distance between plates (d) = 0.3cm = 0.3/100 = 0.003 m

V = potential difference = 935v

A)

Recall that for a capacitor that V = Ed

Where E = strength of electric field.

935 = E× 0.003

E = 935/ 0.003

E = 311,666.7 V/m

B)

C =qV

Where q = magnitude of charge on capacitor.

We need to get the value for C before we can get for q.

C =ε0×A/d

Where ε0 =permittivity of free space = 8.85×10^-12

Hence we have that

C = 8.85×10^-12 × 49/ 0.003

C = 4.32×10^-10/0.003

C = 1.44×10^-7 F

But C=qV

1.44×10^-7 = q (935)

q = 1.54×10^-10c

C)

F=Eq

Where E = strength of electric field = 311,666.7 V/m, q = 1.54×10^-10c

F = 311,666.7 × 1.54×10^-10

F = 4.799×10^-5 N

D)

Total energy stored = cv²/2

Total energy = 1.44×10^-7 × 935²/2

Total energy = 0.0629 J

4 0
2 years ago
A hollow cylinder with an inner radius of 4 mm and an outer radius of 25 mm conducts a 4-A current flowing parallel to the axis
ivann1987 [24]

Answer:

2.1 × 10⁻⁵ T

Explanation:

Given:

Inner radius, r = 4 mm = 0.004 m

Outer radius, R = 25 mm = 0.025 m

Current, I = 4 A

Distance of the point from the center, a = 17 mm = 0.017 m

μ₀ = 4π × 10⁻⁷ T·m/A

Now,

For the hollow cylinder magnetic field (B) is given as:

B=\frac{\mu_0 I(a^2-r^2)\textup{}}{2\pi a(R^2-r^2)\textup{}}

on substituting the respective values, we get

B=\frac{4\pi\times10^{-7}\times4(0.017^2-0.004^2)\textup{}}{2\pi\times0.017(0.025^2-0.004^2)\textup{}}

or

B = 2.1 × 10⁻⁵ T

5 0
3 years ago
Someone please help me<br>20 POINTS
Marta_Voda [28]
1: B 
2: C <span>Sediments were deposited in continuous sheets that spanned the body of water that they were deposited in</span>
3: A Erosion is the action and movement of a surface process
7 0
3 years ago
you are the science officer on a visit to a distant solar system. prior to landing on a planet you measure its diameter to be 1.
Eduardwww [97]

The mass of the star of the distant solar system is 82 * 10²² kg and the mass of the planet of the distant solar system is 8.58 * 10²⁵ kg

The planet stays in its orbit and moves in a centripetal motion due to the gravitational force of attraction between the planet and the star.

Fc = m v² / r

Fg = G M m / r²

Fc = Fg

m v² / r = G M m / r²

v² = G M / r

M = r v² / G

g = Acceleration due to gravity

G = Gravitational constant

M = Mass of star

r = Distance between both bodies

G = 6.67 * 10⁻¹¹ N m² / kg²

r = 8.6 * 10¹¹ m

T = 402 days = 3.47 * 10⁷ s

v = 2 π r / T

v = 2 * 3.14 * 8.6 * 10¹¹ / 3.47 * 10⁷

v = 15.56 * 10⁴ m / s

Ms = 8.6 * 10¹¹ * 15.56 * 10⁴ / ( 6.67 * 10⁻¹¹ )

Ms = 20.1 * 10²⁶ kg

F = G M m / r²

F = m g

Equating,

m g = G M m / r²

Mp = g r² / G

Mp = 63.6 * ( 1.8 * 10⁷ / 2 )² / 6.67 * 10⁻¹¹

Mp = 8.58 * 10²⁵ kg

To know more about Orbital velocity

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3 0
9 months ago
1. A ray of light traveling from air into crown glass strikes the surface at an angle of 30 degrees. What will the
Readme [11.4K]

Answer: acute

Explanation:

4 0
3 years ago
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