Answer: thier salaries are $5000 and $5500
Step-by-step explanation:
Let the average weekly salary of one employee be =x
And that of the other employee be = x+500
Such that if thier average of their salaries= $5250
So, their total salary= $5250 x 2=10,500
The equation to solve each employee salary becomes
x+x+500=10,500
2x+500=10,500
2x=10,500-500
2x=10,000
x=10,000 /2
x= first employee salary =$5000
second employee = x+500 =$5500
5 would be the digit in the tenths place
Answer:
Step-by-step explanation:
1. Null hypothesis: u <= 0.784
Alternative hypothesis: u > 0.784
2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation
Using the formula
sd = √[{P (1-P)}/n]
Where P = 0.84 and n = 750
sd =√[{0.84( 1- 0.84)/750]}
sd=√(0.84 (0.16) /750)
SD =√(0.1344/750)
sd = √0.0001792
sd = 0.013
Then using this we can find z
z = (p - P) / sd
z = (0.84-0.784) / 0.013
z =(0.056/0.013)
z = 4.3077
3. Find the p value and use it to make conclusions...
The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.
4. Conclusions: the results is significant at 0.02 level of significance suck that we can conclude that its on-time arrival rate is now higher than 78.4%.
Below is the solution:
A(final)=16cm^2 ds/dT=6 da/dT=?
<span>A=(s)^2 A=16cm^2 , s=sqrt(A) , s=sqrt(16) , s=4cm </span>
<span>da/dT=2(s)(6cm/sec) , da/dT=12cm/sec(s) , da/dT=12cm/sec (4cm)
</span>
<span>Answer should be da/dT=48cm^2/sec
</span>
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Answer: 22
Step-by-step explanation:
