Help in my home work! convert 80°c to fahrenheit?

A 0.110-kg cube of ice (frozen water) is floating in glycerine. The glycerine is in a tall cylinder that has an inside radius of

creativ13 [48]

Answer

Δ h = 0.06 m

Explanation:

Given,

mass of ice cube = 0.11 Kg

inside radius of cylinder = 3.70 cm

density of water = 1000 Kg/m³

density of glycerin = 1260 Kg/m³

ice cube is floating on glycerin surface,

net force on the cube is equal to zero.

Buoyant force by glycerin is equal to the weight of cube

B = W

$\rho_g V g = m g$

$\rho_g (\pi r^2 h_1)= m$

$h_1= \dfrac{m}{\rho_g\pi r^2}$

$h_1= \dfrac{0.11}{1260\pi\times 0.037^2}$

h₁ = 0.0203 m

when ice melts it is completely turned into water

Volume of mass m of water

$V = \dfrac{m}{\rho_w}$

$\pi r^2 h_2 = \dfrac{m}{\rho_w}$

$h_2 = \dfrac{m}{\rho_w\pi r^2}$

$h_2 = \dfrac{0.11}{1000\pi\times 0.037^2}$

h₂ = 0.0803 m

distance by which height of liquid change

Δ h = h₂ - h₁

Δ h = 0.0803 - 0.0203

Δ h = 0.06 m

6 0

3 years ago

Which of the following is a type of energy that reaches the Earth from the Sun?

elena-s [515]

All of the energy from the Sun that reaches the Earth arrives as solar radiation, part of a large collection of energy called the electromagnetic radiation spectrum. Solar radiation includes visible light, ultraviolet light, infrared, radio waves, X-rays, and gamma rays. Radiation is one way to transfer heat.

7 0

3 years ago

Read 2 more answers

Determine the energy required to accelerate an electron between each of the following speeds. (a) 0.500c to 0.900c MeV (b) 0.900

Aleonysh [2.5K]

Answer:

The energy required to accelerate an electron is 0.582 Mev and 0.350 Mev.

Explanation:

We know that,

Mass of electron $m_{e}=9.11\times10^{-31}\ kg$

Rest mass energy for electron = 0.511 Mev

(a). The energy required to accelerate an electron from 0.500c to 0.900c Mev

Using formula of rest,

$E=\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{f}^2}{c^2}}}-\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{i}^2}{c^2}}}$

$E=\dfrac{0.511}{\sqrt{1-\dfrac{(0.900c)^2}{c^2}}}-\dfrac{0.511}{\sqrt{1-\dfrac{(0.500c)^2}{c^2}}}$

$E=0.582\ Mev$

(b). The energy required to accelerate an electron from 0.900c to 0.942c Mev

Using formula of rest,

$E=\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{f}^2}{c^2}}}-\dfrac{E_{0}}{\sqrt{1-\dfrac{v_{i}^2}{c^2}}}$

$E=\dfrac{0.511}{\sqrt{1-\dfrac{(0.942c)^2}{c^2}}}-\dfrac{0.511}{\sqrt{1-\dfrac{(0.900c)^2}{c^2}}}$

$E=0.350\ Mev$

Hence, The energy required to accelerate an electron is 0.582 Mev and 0.350 Mev.

4 0

4 years ago

Which action is mostly likely to make the team on the left win

Lady bird [3.3K]

D. adding one student to the team on the left

7 0

3 years ago

If the height of the ramp is increased then the marble's speed will be greater because gravity will have less resistance when pu

Alik [6]

If you increase the steepness of the ramp, then you will increase the acceleration of a ball which rolls down the ramp. This can be seen in two different ways:

1) Components of forces. Forces are vectors and have a direction and a magnitude. The force of gravity points straight down, but a ball rolling down a ramp doesn't go straight down, it follows the ramp. Therefore, only the component of the gravitational force which points along the direction of the ball's motion can accelerate the ball. The other component pushes the ball into the ramp, and the ramp pushes back, so there is no acceleration of the ball into the ramp. If the ramp is horizontal, then the ball does not accelerate, as gravity pushes the ball into the ramp and not along the surface of the ramp. If the ramp is vertical, the ball just drops with acceleration due to gravity. These arguments are changed a bit by the fact that the ball is rolling and not sliding, but that only affects the magnitude of the acceleration but not the fact that it increases with ramp steepness. 

2) Work and energy. The change in potential energy of the ball is its mass times the change in height (only the vertical component counts -- horizontal displacements do not change gravitational potential energy) times the local gravitational acceleration g. This loss of gravitational potential energy shows up as an increase in kinetic energy. If the ball falls a farther distance vertically, it will have a greater kinetic energy and be going faster. Again, the kinetic energy is shared between the motion of the ball going somewhere, and the rotation of the ball, and so the details of the acceleration depend on the ball (is it hollow or solid?), but the dependence on the steepness of the ramp is the same.

7 0

3 years ago

Help in my home work!convert 80°c to fahrenheit?​

Help in my home work!convert 80°c to fahrenheit?