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Mandarinka [93]
3 years ago
12

A powerful motorcycle can produce an acceleration of 3.50 m/s2 while traveling at 90.0 km/h. At that speed the forces resisting

motion, including friction and air resistance, total 425 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What is the magnitude (in N) of the force the motorcycle exerts backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 240 kg?
Physics
1 answer:
IrinaK [193]3 years ago
5 0

Answer:1265 N

Explanation:

Given

acceleration of motorcycle \left ( a\right )=3.5 m/s^2

Velocity \left ( v\right )=90 km/h\approx 25m/s

Air friction and Friction\left ( f\right )=425 N

mass of the motorcycle with rider\left ( m\right )=240 Kg

Applying Forces on motorcycle

F_{engine}-f=ma

F_{engine}=f+ma

F_{engine}=425+240\left ( 3.5\right )

F_{engine}=425+840=1265 N

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What is the most important consideration for environmental policy makers?
Nutka1998 [239]
The most important consideration for environmental policy makers would be : environmental health
The basic purpose in creating environmental policy is maintaining the health of the population. the policies that created by the policy makers should be created to prevent any type of damage to population's well being

hope this helps
8 0
3 years ago
A spherical, conducting shell of inner radius r1= 10 cm and outer radius r2 = 15 cm carries a total charge Q = 15 μC . What is t
lutik1710 [3]

a) E = 0

b) 3.38\cdot 10^6 N/C

Explanation:

a)

We can solve this problem using Gauss theorem: the electric flux through a Gaussian surface of radius r must be equal to the charge contained by the sphere divided by the vacuum permittivity:

\int EdS=\frac{q}{\epsilon_0}

where

E is the electric field

q is the charge contained by the Gaussian surface

\epsilon_0 is the vacuum permittivity

Here we want to find the electric field at a distance of

r = 12 cm = 0.12 m

Here we are between the inner radius and the outer radius of the shell:

r_1 = 10 cm\\r_2 = 15 cm

However, we notice that the shell is conducting: this means that the charge inside the conductor will distribute over its outer surface.

This means that a Gaussian surface of radius r = 12 cm, which is smaller than the outer radius of the shell, will contain zero net charge:

q = 0

Therefore, the magnitude of the electric field is also zero:

E = 0

b)

Here we want to find the magnitude of the electric field at a distance of

r = 20 cm = 0.20 m

from the centre of the shell.

Outside the outer surface of the shell, the electric field is equivalent to that produced by a single-point charge of same magnitude Q concentrated at the centre of the shell.

Therefore, it is given by:

E=\frac{Q}{4\pi \epsilon_0 r^2}

where in this problem:

Q=15 \mu C = 15\cdot 10^{-6} C is the charge on the shell

r=20 cm = 0.20 m is the distance from the centre of the shell

Substituting, we find:

E=\frac{15\cdot 10^{-6}}{4\pi (8.85\cdot 10^{-12})(0.20)^2}=3.38\cdot 10^6 N/C

4 0
3 years ago
A steel piano wire, of length 1.150 m and mass 4.80 g is stretched under a tension of 580.0 N.
kaheart [24]

A steel piano wire, of length 1.150 m and mass of 4.80 g is stretched under a tension of 580.0 N.the speed of transverse waves on the wire would be  372.77 m/s

<h3>What is a sound wave?</h3>

It is a particular variety of mechanical waves made up of the disruption brought on by the movements of the energy. In an elastic medium like the air, a sound wave travels through compression and rarefaction.

For calculating the wave velocity of the sound waves generated from the piano can be calculated by the formula

V= √F/μ

where v is the wave velocity of the wave travel on the string

F is the tension in the string of piano

μ is the mass per unit length of the string

As given in question a steel piano wire, of length 1.150 m and mass of 4.80 g is stretched under a tension of 580.0 N.

The μ is the mass per unit length of the string would be

μ = 4.80/(1.150×1000)

μ = 0.0041739 kg/m

By substituting the respective values of the tension on the string and the density(mass per unit length) in the above formula of the wave velocity

V= √F/μ

V=√(580/0.0041739)

V =  372.77 m/s

Thus,  the speed of transverse waves on the wire comes out to be  372.77 m/s

Learn more about sound waves from here

brainly.com/question/11797560

#SPJ1

6 0
1 year ago
The amount of energy carried by a wave and the waves maximum displacement from the rest position describe what?
Mademuasel [1]
What you are describing is Amplitude.
6 0
3 years ago
Xavier is administering medication to his patient. He administers four cups 4 points
Galina-37 [17]

Answer:

11 ounces

Explanation:

The patient gets 11 ounces of liquid.

From the description of this problem:

        Xavier administers  four cups of liquid each containing two ounces

The number of ounces in the four cups = 2 x 4  = 8ounces

Also,

   One cup of the liquid contains 3 ounces.

Total number of ounces administered  = 8 + 3  = 11 ounces.

6 0
3 years ago
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