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Mandarinka [93]

4 years ago

12

A powerful motorcycle can produce an acceleration of 3.50 m/s2 while traveling at 90.0 km/h. At that speed the forces resisting

motion, including friction and air resistance, total 425 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What is the magnitude (in N) of the force the motorcycle exerts backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 240 kg?

1 answer:

IrinaK [193]4 years ago

5 0

Answer:1265 N

Explanation:

Given

acceleration of motorcycle $\left ( a\right )=3.5 m/s^2$

Velocity $\left ( v\right )=90 km/h\approx 25m/s$

Air friction and Friction $\left ( f\right )=425 N$

mass of the motorcycle with rider $\left ( m\right )=240 Kg$

Applying Forces on motorcycle

$F_{engine}-f=ma$

$F_{engine}=f+ma$

$F_{engine}=425+240\left ( 3.5\right )$

$F_{engine}=425+840=1265 N$

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