You should solve this like you would any algebraic expression. Divide both sides by acceleration (a) and you will isolate the mass (m) to one side. Now divide the force (f) by acceleration (a).
F/a=m
This is a projectile motion problem, so, we use the formula for trajectory:
y =xtanα + gx^2/2v^2(cosα)^2
where
y is the vertical distance (y = 50 m)
x is the horizontal distance (x=90 m)
α is the angle of trajectory; since it levels of HORIZONTALLY, α = 0°
v is the initial velocity
g is the acceleration due to gravity which is 9.81 m/s^2
Substituting to the formula,
50 =90tan(0°) + (9.81)(90)^2/2v^2(cos0°)^2
v = 28.2 m/s
Explanation:
As we know that
time = distance/speed
The time used for firs half of the trip was
(1 mi)(12 mi/hour) = 1/12 hours = 5 minutes
The last half of the trip will took 10 minutes, 1/6 hour.
Speed = distance/ time
(1 mil) = (1/6h) = 6 mil/h
so the speed for last half of the trip was = 6mph
the average speed was
(2mil)(1/4 hour) = 8 mil/hour
So the ling's average speed was 8mph.
Explanation:
Given that,
Area enclosed by a brass bracelet, 
Initial magnetic field, 
The electrical resistance around the circumference of the bracelet is, R = 0.02 ohms
Final magnetic field, 
Time, 
The expression for the induced emf is given by :
= magnetic flux
So, the induced emf in the bracelet is 0.678 volts.
Using ohm's law to find the induced current as :
V = IR
I = 33.9 A
or
I = 34 A
So, the induced current in the bracelet is 34 A. Hence, this is the required solution.
