CH4+ 2O2---> CO2+ 2H2O I believe would be correct.
The constant variable is the math problems, the dependent variable is the calculators, and the independent variables are the students
- Glucose = C₆H₁₂O₆.
- Atomic mass of C = 12 u
- Atomic mass of H = 1 u
- Atomic mass of O = 16 u
- Therefore, the molecular mass of glucose
- = (6 × Atomic mass of C) + (12 × Atomic mass of H) + (6 × Atomic mass of O)
- = (6 × 12) + (12 × 1) + (6 × 16) u
- = 72 + 12 + 96 u
- = 180 u
<u>Answer</u><u>:</u>
<u>1</u><u>8</u><u>0</u><u> </u><u>u</u>
Hope you could understand.
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Answer:
A. Dipole-dipole forces; B. dipole-dipole forces;
C. ion-dipole forces; D. ion-dipole forces
Explanation:
A. HF
HF is a weak acid but a highly polar molecule. The strongest intermolecular force with water is an especially strong dipole-dipole force (hydrogen bonding) of the type
H-F· · ·H-OH and H₂O· · ·H-F
B. CH₃OH
CH₃OH has a highly polar O-H bond. The strongest intermolecular force with water is the especially strong dipole-dipole force (hydrogen bonding):
CH₃(H)O· · ·H-OH and CH₃O-H· · ·OH₂
C. CaCl₂
CaCl₂(s) ⟶Ca²⁺(aq) + 2Cl⁻(aq)
CaCl₂ separates into hydrated ions in solution. The strongest intermolecular force with water is ion-dipole attraction.
Ca²⁺· · ·OH₂ and Cl⁻· · ·H-OH
D. FeBr₃
FeBr₃(s) ⟶Fe³⁺(aq) + 3Br⁻(aq)
FeBr₃ separates into hydrated ions in solution. The strongest intermolecular force with water is ion-dipole attraction.
Fe³⁺· · ·OH₂ and Br⁻· · ·H-OH
The answer is that the baseball travels 40 miles per hour