Answer:
The correct answer is option C.
Explanation:
A. The -COOH group would experience hydrogen bonding with water.
The statement is true because , double bonded oxygen atom of carboxylic group interacts with hydrogen atom of water molecule and oxygen atom of water molecule is in same interaction with hydrogen atom of carboxylic acid.
B. The long alkane ''tail"
, is hydrophobic.
The statement is true because , region which do not interacts with water molecule is termed as hydrophobic region and region which do interacts with water molecule is termed as hydrophilic region. Generally ,alkanes are are hydrophobic in nature so is the alkane chain in stearic acid.
C. Stearic acid and water are probably miscible.
The statement is false because of higher hydrophobic region the interaction between the acid molecules and water molecules results in immiscibility.
D. Stearic acid would probably dissolve in non polar solvents such as hexane
.
The statement is true because of hydrophobic part in stearic acid is larger so that is why it get easily dissolve in non polar solvents.
E. Stearic acid contains hydrophobic regions
The statement is true because of higher hydrophobic region due to which they easily get dissolved in organic and non polar solvents.
Answer:
Element X is Arsenic (As)
Explanation:
- Elements in the periodic table are either metals, non-metals or metalloids.
- Metals are elements that react by losing electrons to obtain a stable configuration and form cation.
- Non-metals are those elements that react by gaining electrons to form a stable configuration and form anion.
- Metalloids are elements in the periodic table that have both metallic and non-metallic properties.
- Examples of metalloids include Selenium, Arsenic, Boron, etc.
- Arsenic is a metalloid in period 4 (four energy levels) with five valence electrons.
Answer: burning paper
Explanation:
The paper burns in air to form smoke and ash. which makes it a chemical change.
Let's say say there are n1 mols of helium in the first balloon and n2 mols of nitrogen in the second one, which are equivalent to m1 grams of helium and m2 grams of nitrogen.
The molar mass of hydrogen is thus M1=m1/n1, same for nitrogen M2=m2/n2 hence the ratio of their masses is m1/m2=(M1n1)/(M2n2). Since both gases are rather similar, we can assume that n1~n2 hence m1/m2=M1/M2
Explanation:
I think the answer is 2nd