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seraphim [82]
4 years ago
10

What statement is true because of Newton's Second Law?

Physics
2 answers:
velikii [3]4 years ago
8 0
<span>C. When the net force of an object decreases, the acceleration decreases

'cause they both are directly proportional to each other

Hope this helps!
</span>
andreyandreev [35.5K]4 years ago
3 0

was the answer even right


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Newton's law of Universal Gravitation says that one particle attracts the rest of every other particle in the universe using a force that is directly equivalent to the product of their masses and inversely equivalent to the square of the distance between them.
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3 years ago
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g If the x-component of a force vector is 5.69 newtons and its y-component is 8.00 newtons, then what is its magnitude?
beks73 [17]

Answer:

F = 9.82 N

Explanation:

given,

Force x-component = 5.69 N

Force y-component = 8 N

magnitude of force = ?

Resultant of force

F = \sqrt{F_x^2 + F_y^2}

F = \sqrt{5.69^2 + 8^2}

F = \sqrt{32.3761 + 64}

F = \sqrt{96.3761}

F = 9.82 N

Hence, the magnitude of force is equal to 9.82 N

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3 years ago
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A cheetah can run at a maximum speed 97.8 km/h and a gazelle can run at a maximum speed of 78.2 km/h. If both animals are runnin
emmainna [20.7K]

(1)

Cheetah speed: v_c = 97.8 km/h=27.2 m/s

Its position at time t is given by

S_c (t)= v_c t (1)

Gazelle speed: v_g = 78.2 km/h=21.7 m/s

the gazelle starts S0=96.8 m ahead, therefore its position at time t is given by

S_g(t)=S_0 +v_g t (2)

The cheetah reaches the gazelle when S_c=S_g. Therefore, equalizing (1) and (2) and solving for t, we find the time the cheetah needs to catch the gazelle:

v_c t=S_0 + v_g t

(v_c -v_g t)=S_0

t=\frac{S_0}{v_c-v_t}=\frac{96.8 m}{27.2 m/s-21.7 m/s}=17.6 s


(2) To solve the problem, we have to calculate the distance that the two animals can cover in t=7.5 s.

Cheetah: S_c = v_c t =(27.2 m/s)(7.5 s)=204 m

Gazelle: S_g = v_g t =(21.7 m/s)(7.5 s)=162.8 m

So, the gazelle should be ahead of the cheetah of at least

d=S_c -S_g =204 m-162.8 m=41.2 m

4 0
3 years ago
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Tonya is thinking about the topic presented in the text, "Do opposites really attract?" Which of her thoughts is an example of c
tigry1 [53]

tanya is dumb  j j j j j j j j j jj j j j

6 0
3 years ago
An irregular object of mass 3 kg rotates about an axis, about which it has a radius of gyration of 0.2 m, with an angular accele
Citrus2011 [14]

Answer:

The magnitude of the applied torque is 6.0\times10^{-2}\ N-m

(e) is correct option.

Explanation:

Given that,

Mass of object = 3 kg

Radius of gyration = 0.2 m

Angular acceleration = 0.5 rad/s²

We need to calculate the applied torque

Using formula of torque

\tau=I\times\alpha

Here, I = mk²

\tau=mk^2\times\alpha

Put the value into the formula

\tau=3\times(0.2)^2\times0.5

\tau=0.06\ N-m

\tau=6.0\times10^{-2}\ N-m

Hence, The magnitude of the applied torque is 6.0\times10^{-2}\ N-m

7 0
4 years ago
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