Ask question

Ask question

All categories

2 years ago

8

What are air pollutants

1 answer:

KIM [24]2 years ago

5 0

Answer:

things that pollute the air

Explanation:

nuclear energy, fossil fuels, gas from cars and other transportation, and these all contribute to greenhouse gases that are harmful to the environment

hope this helped!

You might be interested in

Your friend, a business major, overhears you talking about chemical energy and food and decides to develop a new super food for

RUDIKE [14]

Answer:

The question is incomplete. The response options are as follows:

I. C-O or C=O

II. C-C

III. C-H

IV. O-H

The answer is: IV>III>I>II

Explanation:

V) O-H is a hydrogen bridge. The hydrogen bridge is characterized by being similar to dipole-dipole bonds.

III) C-H is an ionic bond. The ionic bond occurs when they fuse together due to electron transfer.

I) C=O is a covalent bond. The covalent bond happens when two atoms bond together to create a molecule, sharing its electrons that are in its most superficial layer,

II) C-C is covalent bond.

7 0

3 years ago

How do chemicals in a plant relate to bath bombs?

OLga [1]

When a bath bomb comes in contact with water, the baking soda and citric acid react to make carbon dioxide bubbles. This is an acid–base reaction, where baking soda (also called sodium bicarbonate) is a weak base and citric acid is a weak acid.

3 0

3 years ago

A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago

How many pounds in a 3.00 l bottle of drinking water?

slava [35]

Answer:

6.61 Pounds

Solution:

Step 1: Calculate Mass of Water as;

Density = Mass ÷ Volume

Solving for Mass,

Mass = Density × Volume ------ (1)

As,

Density of Water = 1 g.cm⁻³

And,

3 L of Water = 3000 cm³

Putting values in equation 1,

Mass = 1 g.cm⁻³ × 3000 cm³

Mass = 3000 g

Step 2: Convert Grams into Pounds;

As,

1 Gram = 0.002204 Pounds

So,

3000 Grams = X Pounds

Solving for X,

X = (3000 Grams × 0.002204 Pounds) ÷ 1 Gram

X = 6.61 Pounds

6 0

3 years ago

What is the density of a block marble that occupies 255 cm^3 and has a mass of 1000g

RUDIKE [14]

Answer:

<h2>3.92 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{1000}{255} \\ = 3.921568...$

We have the final answer as

<h3>3.92 g/cm³</h3>

Hope this helps you

4 0

3 years ago