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marin [14]
3 years ago
6

Calculate the new pressure of a gas if the gas at 50 ˚C and 81.0 kPa is heated to 100 ˚C at a constant volume.

Chemistry
1 answer:
Debora [2.8K]3 years ago
7 0

Answer:

93.5 kPa

Explanation:

Step 1: Given data

  • Initial pressure (P₁): 81.0 kPa
  • Initial temperature (T₁): 50 °C
  • Final pressure (P₂): ?
  • Final volume (T₂): 100 °C

Step 2: Convert the temperatures to the Kelvin scale

When working with gases, we need to consider the absolute temperature. We will convert from Celsius to Kelvin using the following expression.

K = °C + 273.15

T₁: K = 50°C + 273.15 = 323 K

T₂: K = 100°C + 275.15 = 373 K

Step 3: Calculate the final pressure of the gas

At a constant volume, we can calculate the final pressure of the gas using Gay-Lussac's law.

P₁/T₁ = P₂/T₂

P₂ = P₁ × T₂/T₁

P₂ = 81.0 kPa × 373 K/323 K

P₂ = 93.5 kPa

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3 years ago
When methyloxirane is treated with HBr, the bromide ion attacks the less substituted position. However, when phenyloxirane is tr
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Answer:

See explanation and picture below

Explanation:

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In both cases, the H atom of the HBr goes to the oxygen in the molecule. You'll have a OH⁺ in both. However, in the case of methyloxirane the next step is a Sn2 mechanism step, the bromide ion will go to the less substitued carbon, because the methyl group is exerting a steric hindrance. Not a big one but it has a little effect there, that's why the bromide will rather go to the carbon with more hydrogens. and the final product is formed.

In the case of phenyloxirane, once the OH⁺ is formed, the next step is a Sn1 mechanism. In this case, the bond C - OH⁺ is opened on the side of the phenyl to stabilize the OH. This is because that carbon is more stable than the carbon with no phenyl. (A 3° carbon is more stable than a 2° carbon). Therefore, when this bond opens, the bromide will go there in the next step, and the final product is formed. See picture below for mechanism and products.

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Answer:

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