I think 7a^3b^6, but im not sure so im sorry if it is wrong
Let's try to divide the sentence into multiple parts and then combine it one by one to make it easier to understand.
1. True
2 times y and 6 -------->(2y+6)
the square of the sum of "2 times y and 6" -------->(2y+6)^2
8 times "the square of the sum of 2 times y and 6"------> 8(2y+6)^2
2. True
the difference of x and 7 -------->(x-7)
9 and x -------->(9 + x)
2 times the product of the sum of
"9 and x" and "the difference of x and 7"-------> 2(9 + x) (x-7)
3. True
difference of 5 times x and 3 -------->(5x-3)
the square of the difference of 5 times x and 3------->(5x-3)^2
4. False
The description should be: the product of 7 and the square of x
the product of 7 and x -------->(7x)
the square of the product of 7 and x -------->(7x)^2
5. True
This one should be clear as it was one sentences
the sum of y squared(y^2) and three times y(3y) minus 4-------->y^2+ 3y -4
6. False
The description should be: the product of 5 and 8 times the square of x plus the sum of 20x and 8
the sum of 20x and 8 -------->20x+8
8 plus the square of x plus the sum of 20x and 8-------->8+ x^2 +20x+8
the product of 5 and.... ------->(5)(........
the product of 5 and
8 plus the square of x plus the sum of 20x and 8---->(5)(8+ x^2 +20x+8)
Answer:
Ordered pairs are ( -3, 0) (0, 3)
Step-by-step explanation:
Now when your graphing, go up 3 spots in the y-axis ( up & down) and plot your point now do the same for your x-axis (( left and right), so go over to the left 3 places, and there now connect the 2 points and your done. Hope that helps!
No, the tangent line needs to be against the circle from where it leaves. This is just a straight up right angle.
Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
