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andrew11 [14]
3 years ago
12

What can you do to mitigate these risks?

Physics
1 answer:
andrey2020 [161]3 years ago
7 0

Answer: your question is incomplete, however I want you to know that there are four ways to mitigate a risk, these are:

avoid, accept, reduce/control, or transfer. Whatever the risk in your question is, it will definitely fit into any of the aforemened risk strategies.

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A person is sitting with one leg outstretched and stationary, so that it makes an angle of θ = 27.5° with the horizontal, as the
dangina [55]

here we will use the torque balance about the knee joint

here we can say that

\tau_g = \tau_m

here torque due to weight is given as

\tau_g = 40.1 cos\theta*(l_1 + l_2)

\tau_g = 40.1 cos27.5*(0.105 + 0.150)

\tau_g = 9.07 Nm

now torque due to applied force of muscle

\tau_m = M*sin\alpha * l_1

\tau_m = M*sin30* 0.105

now by torque balance we will have

9.07 = M*0.5*0.105

M = 173 N

so here the magnitude of m will be 173 N

7 0
3 years ago
Does a 2000 mercury cougar have a timing belt
Katena32 [7]
No it does not have a timing belt
5 0
3 years ago
Which representation shows the relationship between resistance and the length of a wire?
dybincka [34]

Answer:

R∝L

Explanation:

7 0
3 years ago
What are ways to improve the design of this experiment? Check all that apply
Serhud [2]

Answer:

B,D,E

Explanation:

I got you

B. Experiment with a wider range of materials.

D.Use a laboratory galvanometer to make precise measurements.

E. Test the strength of the electromagnet by varying the number of wire coils.

3 0
3 years ago
The Steamboat Geyser in Yellowstone National Park shoots water into the air at 48.0 m/s. How
qwelly [4]

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Given;

initial velocity of the water, u = 48 m/s

at maximum height the final velocity will be zero, v = 0

the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².

The maximum height reached by the water is calculated as follows;

v² = u² + 2gh

where;

h is the maximum height reached by the water

0 = u² + 2gh

0 = (48)² + ( 2 x -9.8 x h)

0 = 2304 - 19.6h

19.6h = 2304

h = 2304 / 19.6

h = 117.55 m

Therefore, the maximum height reached by the water is 117.55 m.

7 0
2 years ago
Read 2 more answers
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