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2 years ago

12

A light beam which is amplified into a strong concetrated beam of light is known as A) a laser. B) a transistor. C) a microwave

oven. D) a light emitting diode.

2 answers:

valentina_108 [34]2 years ago

5 0

Answer:

The answer is (A)!

Explanation:

murzikaleks [220]2 years ago

4 0

The correct answer is A. a <em>Laser</em>.

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In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separatio

Keith_Richards [23]

Answer:

b. 0.25cm

Explanation:

You can solve this question by using the formula for the position of the fringes:

$y=\frac{m\lambda D}{d}$

m: order of the fringes

lambda: wavelength 500nm

D: distance to the screen 5 m

d: separation of the slits 1mm=1*10^{-3}m

With the formula you can calculate the separation of two adjacent slits:

$\Delta y=\frac{(m+1)(\lambda D)}{d}-\frac{m\lambda D }{d}=\frac{\lambda D}{d}\\\\\Delta y=\frac{(500*10^{-9}nm)(5m)}{1*10^{-3}m}=2.5*10^{-3}m=0.25cm$

hence, the aswer is 0.25cm

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2 years ago

Here is a picture showing how two magnets will stick to one another when opposite poles align. When these magnets are pulled sli

7nadin3 [17]

Answer:

C

Explanation:

A magnetic field exerts its force beyond just direct touch.

7 0

2 years ago

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A potter's wheel has the shape of a solid uniform disk of mass 7 kg and radius 0.65 m. It spins about an axis perpendicular to t

ozzi

Answer:

1.832 kgm^2

Explanation:

mass of potter's wheel, M = 7 kg

radius of wheel, R = 0.65 m

mass of clay, m = 2.1 kg

distance of clay from centre, r = 0.41 m

Moment of inertia = Moment of inertia of disc + moment f inertia of the clay

I = 1/2 MR^2 + mr^2

I = 0.5 x 7 x 0.65 x 0.65 + 2.1 x 0.41 x 0.41

I = 1.47875 + 0.353

I = 1.832 kgm^2

Thus, the moment of inertia is 1.832 kgm^2.

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3 years ago

I need help !!!!! Show the work plz!!!!

horrorfan [7]

Answer:

26) 2 meters a second

27) 2 meters a second

28) 5 meters a second

29) 8 km

Explanation:

1/.5 =2

8/4=2

50/10=5

8km×1= 8

7 0

2 years ago

An object's moment of inertia is 2.0 kg · m2. its angular velocity is increasing at the rate of 4.0 rad/s per second. what is th

Deffense [45]

To solve the problem, we can use the equivalent of Newton's second law for rotational motions:
$\tau = I \alpha$
where
$\tau$ is the net torque acting on the object
I is the moment of inertia of the body
$\alpha$ is the angular acceleration of the object.

Using the data of the problem: $I=2.0 kg \cdot m^2$ and $\alpha=4.0 rad/s^2$ , we find the net torque acting on the object:
$\tau=(2.0 kg \cdot m^2)(4.0 rad/s^2)=8.0 N \cdot m$

3 0

2 years ago

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