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3 years ago

12

A light beam which is amplified into a strong concetrated beam of light is known as A) a laser. B) a transistor. C) a microwave

oven. D) a light emitting diode.

2 answers:

valentina_108 [34]3 years ago

5 0

Answer:

The answer is (A)!

Explanation:

murzikaleks [220]3 years ago

4 0

The correct answer is A. a <em>Laser</em>.

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They can.
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3 years ago

At 900.0 K, the equilibrium constant (Kp) for the following reaction is 0.345. 2SO2(g)+O2(g)→2SO3(g) At equilibrium, the partial

elena55 [62]

Answer : The partial pressure of $SO_3$ is, 67.009 atm

Solution : Given,

Partial pressure of $SO_2$ at equilibrium = 30.6 atm

Partial pressure of $O_2$ at equilibrium = 13.9 atm

Equilibrium constant = $K_p=0.345$

The given balanced equilibrium reaction is,

$2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)$

The expression of $K_p$ will be,

$K_p=\frac{(p_{SO_3})^2}{(p_{SO_2})^2\times (p_{O_2})}$

Now put all the values of partial pressure, we get

$0.345=\frac{(p_{SO_3})^2}{(30.6)^2\times (13.9)}$

$p_{SO_3}=67.009atm$

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3 years ago

A very long solid insulating cylinder has radius R = 0.1 m and uniform charge density rho0= 10-3 C/m3. Find the electric field a

Galina-37 [17]

Answer:

$E = (0.56 \times 10^8 ) r \ \ N/c$

Explanation:

Given that:

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To find the electric field for r < R by using Gauss Law

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For r < R

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$E= \dfrac{\rho ( r)}{2 \varepsilon_o}$

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$\varepsilon_o = 8.85 \times 10^{-12}$

$E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}$

$E= \dfrac{10^{-3} ( r)}{2 (8.85 \times 10^{-12})}$

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Lemur [1.5K]

Explanation:

Work cannot be increased by using a machine of some kind.

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3 years ago

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