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andrezito [222]
3 years ago
12

A nurse counts 66 heartbeats in one minute. What is the period of the hearts oscillation? In minutes

Physics
1 answer:
inn [45]3 years ago
7 0

The frequency is  66 / minute .

The period is 1/frequency = minute / 66 =

(60 seconds) / 66 = 0.91 second

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Determine the gravitational potential energy, in kJ, of 3 m3 of liquid water at an elevation of 40 m above the surface of Earth.
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Explanation:

We will calculate the gravitational potential energy as follows.

                 P.E_{1} = mgz_{1}

       P.E_{1} = (\rho V)gz_{1}    

                    = 1000 kg/m^{3} \times 3 m^{3} \times 9.7 \times 40 m

                    = 1164000 J

or,                = 1164 kJ         (as 1 kJ = 1000 J)

Now, we will calculate the change in potential energy as follows.

             \Delta P.E = mg(z_{2} - z_{1})

                         = \rho \times V \times g (z_{2} - z_{1})

                         = 1000 \times 3 \times 9.7 (10 - 40)m

                         = -873000 J

or,                      = -873 kJ

Thus, we can conclude that change in  gravitational potential energy is -873 kJ.

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3 years ago
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3 years ago
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solong [7]

Answer:

= 2 beats per seconds

Explanation:

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These also shows how to get the period of the tuning forks.

7 0
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