The friend has some quiz corrections currently, so anyone who helps thank you.

Mathematics

1 answer:

Tomtit [17]2 years ago

8 0

Answer:

Area = 162 ft.^(2)

Step-by-step explanation:

50% of 18 ft. = 9 ft.

9 x 18 = 162 ft.^(2)

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How to use denominators when comparing two fractions with the same numerators

Sholpan [36]

What you would do is take the denominators and multiply them by each other, then multiply the numerators by that same number. So like 4/10 and 4/9. You would say, (denominators) 10x9=90 and (numerators) 4x9=36. So your first fraction would be 36/90. Next, you would take (denominators) 9x10=90 and (numerators) 4x10=40. So your second fraction would become 40/90. Now it's a lot easier to compare. 36/90 < 40/90 would be the answer to my problem. I hope I helped!

4 0

3 years ago

Read 2 more answers

Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .