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Dafna1 [17]
2 years ago
7

21. A store display will have 6 rows, with 12 containers in each row.

Mathematics
1 answer:
Crazy boy [7]2 years ago
5 0
It should be 39 containers, I’m not sure though
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A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the
Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0
2 years ago
Identify the graphed linear equation.<br> A) y=5x+2<br> B) y=5x-2<br> C) y=-5x+2<br> D) y=-5x-2
soldi70 [24.7K]

Answer: y=-5x-2

Step-by-step explanation: If you type all of the options into desmos calculator you will come up with 4 different graphs. Just simply find the graph with your coordinates on it. hope this helped :)

7 0
2 years ago
MARKING BRAINLIEST!!
Misha Larkins [42]

Answer: 6a 2(a+2a) and the last one

Step-by-step explanation:

7 0
3 years ago
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What is the answer for -4+w=-10
ahrayia [7]
Add 4 to both sides
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3 years ago
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The number of bacteria in a refrigerated food product is given by N ( T ) = 22 T 2 − 123 T + 40 , 6 &lt; T &lt; 36 , where T is
antoniya [11.8K]

Answer:

N(T(t)) = 1408t^2 - 385.6t - 105.52

Time for bacteria count reaching 8019: t = 2.543 hours

Step-by-step explanation:

To find the composite function N(T(t)), we just need to use the value of T(t) for each T in the function N(T). So we have that:

N(T(t)) = 22 * (8t + 1.7)^2  - 123 * (8t + 1.7) + 40

N(T(t)) = 22 * (64t^2 + 27.2t + 2.89) - 984t - 209.1 + 40

N(T(t)) = 1408t^2 + 598.4t + 63.58 -  984t - 169.1

N(T(t)) = 1408t^2 - 385.6t - 105.52

Now, to find the time when the bacteria count reaches 8019, we just need to use N(T(t)) = 8019 and then find the value of t:

8019 = 1408t^2 - 385.6t - 105.52

1408t^2 - 385.6t - 8124.52 = 0

Solving this quadratic equation, we have that t = 2.543 hours, so that is the time needed to the bacteria count reaching 8019.

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3 years ago
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