**Answer:**

A.'C

**Explanation:**

Please answer my question

From the combustion of octane, the formaldehyde will be formed as this equation:

C8H18 + O2 → CH2O + H2O this is the original equation but it is not a balanced equation, so let's start to balance it:

the equation to be balanced so the number of atoms on the right side of the equation sholud be equal with the number of atoms on the lef side.

-we have 8 C atoms on left side and 1 atom on the right side so we will try putting 8 CH2O on the right side instead of CH2O

C8H18 + O2 → 8 CH2O + H2O

we have 2 O atoms on the left side and 9 atoms on the right side so we will try first to put 9 O2 instead of O2 on the left side and put 2H2O on the right side and put 16 CH2O instead of 8 CH2O to make the atoms of O are equal on both sides = 18 atoms

C8H18 + 9 O2 → 16 CH2O + 2H2O

put now we have 8 atom C on the left side and 16 atom on the right side so, we will put 2 C8H18 instead of C8H18 now we get this equation:

2C8H18 + 9O2 →16 CH2O + 2H2O

-now we have 36 of H atoms on both sides.

- and 16 of C atoms on both sides.

- and 18 of O atoms on both sides.

now all the number of atoms of O & C & H are equal on both sides

**∴ 2C8H18 + 9O2 **→** 16 CH2O + 2 H2O **

**is the final balanced equation for the formation of formaldehayde**

Answer:

Water is the solvent

Both the ethanol and the hydrogen peroxide are the solute

Explanation:

Both the hydrogen peroxide and ethanol are sisobable in water.

There are 0.05 moles of ethanol.

1 litreof water contains 55.55 moles of water.

0.2 g of hydrogen peroxide contains 0.2/34 = 0.0059 moles of hydrogen peroxide (the 34 is the molar mass of hydrogen peroxide).

Since there are more moles of water, water becomes the solvent and the other two liquids dissolve in it.

**Answer:**

Molar mass = 27 g/mol

**Explanation:**

**Given data;**

Number of moles of Al = 0.2 mol

Mass of Al = 5.4 g

Molar mass of Al = ?

**Solution:**

**Formula:**

Number of moles = mass/molar mass

By putting values,

0.2 mol = 5.4 g/ molar mass

Molar mass = 5.4 g/ 0.2 mol

Molar mass = 27 g/mol