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Readme [11.4K]
3 years ago
6

If the following elements were to form ions, they would attain the same number of electrons as which noble gas?

Chemistry
1 answer:
kobusy [5.1K]3 years ago
7 0
The elements that form anions will have the electronic configuration similar to the noble gas that is in their period and those that form cations will have a configuration similar to that of the noble gas in the previous period.
He: Be
Ne: F, Al
Ar: Ca, P
Kr: Rb, Se
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Ionic bonds are formed between metal and nonmetal elements. Potassium has only one valence electron and it is stripped away in t
lbvjy [14]
Refer to the table below. Credits to https://terpconnect.umd.edu/~wbreslyn/chemistry/naming/IonicCharge2.jpg 

Cations with (+ ) charges lose electrons in order to obtain an octet (8 valence electrons) when they ionically bond with another ion.  We're looking for the ions that loses electrons here. So, from the table: 

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Since Al and Ag has (+) charges, they are going to lose electrons to form ionic bonds with other atoms.

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Answer:

A. One unpaired electron

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In B, also Fe is in +3 oxidation state but F is weak field ligand hence causes no pairing of Electrons hence it results 5 unpaired electrons with electronic configuration t2g^3 eg^2

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1. If we used 0.0100 moles of K2CO3, how many moles of SrCO3 can be expected to form?​
faltersainse [42]

Answer:

0.01 moles of SrCO₃

Explanation:

In this excersise we need to propose the reaction:

K₂CO₃ + Sr(NO₃)₂  →  2KNO₃ + SrCO₃

As we only have data about the potassium carbonate  we assume the strontium nitrite as the excess reactant.

1 mol of K₂CO₃ react to 1 mol of Sr(NO₃)₂ in order to produce 2 moles of potassium nitrite and 1 mol of strontium carbonate.

Ratio is 1:1. In conclussion,

0.01 mol of K₂CO₃ must produce 0.01 moles of SrCO₃

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3 years ago
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