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worty [1.4K]
4 years ago
7

Calcium Oxide is used to remove pollutant SO2 from smokestack gases. The ΔG° of the overall reaction is -418.6 kJ. What is PSO2

in equilibrium with air (PO2 = 0.21 atm) and solid CaO?
CaO(s)+SO2 (g)+1⁄2O2 (g)⇔CaSO4 (s)
Chemistry
1 answer:
Gwar [14]4 years ago
5 0
From the change in free energy, we can calculate the equilibrium constant by the equation <span>ΔG°=-RT ln(K) where K is the equilibrium constant.

-418.6x10^2 = -(8.314)(298) ln (K)
K = 2.38x10^73

K is expressed as:

K = 1 / Pso2 (Po2)^0.5 = 1/ </span>Pso2 (0.21)^0.5
 2.38x10^73 = 1/ Pso2 (0.21)^0.5
Pso2 = 9.17x10^-74 atm
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A compound is 85.7% C and 14.3% H and has a molar mass of 98g/mol, what is the compounds molecular formula?
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Answer:

Molecular Formula => (CH₂)₇ => C₇H₁₄      

Explanation:

Empirical ratio is calculated from the sequence...

%/100wt => grams/100wt => moles => mole ratio => reduce mole ratio => Empirical Ratio

C: 85.7% => 85.7g => (85.7/12)mol = 7.14 mole

H: 14.3%  => 14.3g =>     (14.3/1)mol = 14.3 mole

C:H mole ratio => 7.14:14.3

Reduced mole ratio (divide by the smaller mole value) => (7.14/7.14):(14.3/7.14) => Empirical Ratio => 1:2 => Empirical Formula => CH₂

Molecular Wt = Whole No. Multiple of Empirical Formula Wt.

M.Wt = N(Emp Wt) => 98g = N(14g) => N = 7

∴Molecular Formula => (CH₂)₇ => C₇H₁₄

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