Calcium Oxide is used to remove pollutant SO2 from smokestack gases. The ΔG° of the overall reaction is -418.6 kJ. What is PSO2
in equilibrium with air (PO2 = 0.21 atm) and solid CaO?
CaO(s)+SO2 (g)+1⁄2O2 (g)⇔CaSO4 (s)
1 answer:
From the change in free energy, we can calculate the equilibrium constant by the equation <span>ΔG°=-RT ln(K) where K is the equilibrium constant.
-418.6x10^2 = -(8.314)(298) ln (K)
K = 2.38x10^73
K is expressed as:
K = 1 / Pso2 (Po2)^0.5 = 1/ </span>Pso2 (0.21)^0.5
2.38x10^73 = 1/ Pso2 (0.21)^0.5
Pso2 = 9.17x10^-74 atm
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