It means 3p (p being your variable) to the third power, or cubed
A science conclusion should simply have a statement identifying whether your experiment’s aim turned out to be true or false
Answer:
Candy
Explanation:
its sweet and has a lot of sugar and acid
<u>Answer:</u> The energy of one photon of the given light is 
<u>Explanation:</u>
To calculate the energy of one photon, we use Planck's equation, which is:

where,
= wavelength of light =
(Conversion factor:
)
h = Planck's constant = 
c = speed of light = 
Putting values in above equation, we get:

Hence, the energy of one photon of the given light is 