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IRISSAK [1]
3 years ago
11

Which substance would require the most energy to heat 10.00 g of it by 10.0°C?

Chemistry
1 answer:
Leviafan [203]3 years ago
8 0

Answer:

a

Explanation:

a

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Does anyone know how to write out the formula for these?? not just the answer x
Tju [1.3M]
Idk how to write the formula I had this same question
5 0
2 years ago
How many half-lives are required for the concentration of reactant to decrease to 1.56% of its original value?4247.56.56
neonofarm [45]

Answer:

6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

Concentration is decreased to 1.56 % which means that 0.0156 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 0.0156

Thus,

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.0156=e^{-k\times t}

kt = 4.1604

The expression for the half life is:-

Half life = 15.0 hours

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

\frac{4.1604}{t}=\frac {ln\ 2}{t_{1/2}}

t = 6\times t_{1/2}

<u>6 half-lives are required for the concentration of reactant to decrease to 1.56% of its original value.</u>

6 0
3 years ago
How many valence electrons does an atom of Iodine have?<br><br> a) 5 <br> b) 6 <br> c) 7 <br> d) 8
baherus [9]
The answer is 7 !! :)
8 0
2 years ago
Read 2 more answers
Write a net ionic equation for the overall reaction that occurs when aqueous solutions of sodium hydroxide and oxalic acid (H2C2
belka [17]

Answer:

Oxalic acid is a dicarboxylic acid and forms sodium salt with NaOH and water

Explanation:

4 0
3 years ago
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How many carbon atoms are there in a 1.5-carat diamond? diamonds are a form of pure carbon. ( 1 carat=0.20 grams)?
11111nata11111 [884]
1 carot = 0.2 grams
1.5 carot = 0.3 grams.

1 mol of Carbon = 12 grams
x mol = 0.3 grams

0.3 * 1 = 12 x
x = 0.3/12
x = 0.025 mol

1 mol of Carbon is 6.02 * 10^23 atoms
0.025 mol of carbon is x

1/0.025 = 6.02*10^23 * /x
x = 0.025 * 6.02 * 10^23
x = 1.5 * 10^22 atoms of carbon.
5 0
2 years ago
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