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3 years ago

5

Alan made the diagram below to represent ultraviolet rays, radio waves, gamma rays, and infrared rays based on their properties.

1 answer:

Ludmilka [50]3 years ago

8 0

The answer would be wave C because because C IS THE BEST ONE IN THE WHOLE WORKD AND SO THATS THE ANWEER NO CAPPP BROO ‼️‼️

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Would the value of "g" be affected if the size of the Bob is varied ?

marshall27 [118]

Answer:

Any variable would be affected if the product is varied.

Explanation:

If you have any questions feel free to ask in the comments - Mark

ALSO Happy Valentines Day ❤

6 0

4 years ago

A meter stick balances horizontally on a knife-edge at the 50.0 cm mark. With two 4.79 g coins stacked over the 28.8 cm mark, th

masha68 [24]

To solve the exercise, the key concept to be addressed is the Mass Center.

The center of mass of an object is measured as,

$X_{cm} = \frac{\sum m_ix_i}{\sum m_i}$

$X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}$

Our values are given by,

$x_1 = 50cm$

$m_1 = ?$

$x_2 =28.8cm$

$m_2 = 4.79g$

$x_3 = 28.8cm$

$m_3 = 4.79g$

$X_{cm} = 38.4cm$

Replacing the values in our previous equation we have,

$X_{cm} = \frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}$

$38.4 = \frac{m_1(50)+2(28.8*4.79)}{m_1+2*4.79}$

$38.4(m_1+2*4.79)= m_1(50)+2(28.8*4.79)$

$38.4m_1 +367.872 = 50m_1+275.904$

$11.6m_1 = 91.968$

$m_1 = 7.928g$

Therefore the mass of the meter stick is 7.928g

7 0

3 years ago

Calculate the wavelength and frequency at which the intensity of the radiation is a maximum for a blackbody at 298 K. You will n

Juliette [100K]

Answer:

Wavelength, $\lambda=9.72\times 10^{-6}\ m$

Frequency, $f=3.08\times 10^{13}\ Hz$

Explanation:

We need to find the intensity of the radiation is a maximum for a black body at 298 K. It can be calculated using Wein's displacement law. It is given by :

$\lambda T=2.898\times 10^{-3}\ m-K$

$\lambda=\dfrac{2.898\times 10^{-3}}{T}$

Here, T = 298 K

$\lambda=\dfrac{2.898\times 10^{-3}}{298}$

$\lambda=9.72\times 10^{-6}\ m$

If f is the frequency of black body radiation. It is given by :

$f=\dfrac{c}{\lambda}$

$f=\dfrac{3\times 10^8}{9.72\times 10^{-6}}$

$f=3.08\times 10^{13}\ Hz$

Hence, this is the required solution.

6 0

3 years ago

Compare each pair of numbers using <, > or =.

Effectus [21]

Answer:

A. 56 cm < 6 m

B. 7 g > 698 mg

C. 19 g > .021k

4 0

3 years ago

Which of these materials are insulators? Select the THREE (3) that apply.

Mashutka [201]

Answer: wool, rubber, & plastic

Explanation: Insulators slow transfer.

5 0

3 years ago