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PolarNik [594]
3 years ago
5

Alan made the diagram below to represent ultraviolet rays, radio waves, gamma rays, and infrared rays based on their properties.

Physics
1 answer:
Ludmilka [50]3 years ago
8 0
The answer would be wave C because because C IS THE BEST ONE IN THE WHOLE WORKD AND SO THATS THE ANWEER NO CAPPP BROO ‼️‼️
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How to find acceleration?
Marat540 [252]

Answer:

a=(v-u)/t is how you find acceleration.

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3 years ago
Which two statements describe how ultrasound technology produces an image of a baby before it is born?
Elan Coil [88]

Answer:a and c

Explanation:

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The acceleration due to gravity is
Gnesinka [82]

Answer:

9.8 m/s^2

Explanation:

This is a constant that you should memorize

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3 years ago
El motor de una licuadora gira a 3600 rpm, disminuye su velocidad angular hasta 2000 rpm realizando 120 vueltas. Calcular: a) La
allsm [11]

Answer:

a) α = -65,2 rad/s².

b) t = 2,57 s.

Explanation:

a) La aceleración angular se puede calcular usando la siguiente ecuación:

\omega_{f}^{2} = \omega_{0}^{2} + 2\alpha \theta

En donde:

\omega_{f}: es la velocidad angular final =  2000 rpm = 209,4 rad/s

\omega_{0}: es la velocidad angular inicial = 3600 rpm = 377,0 rad/s

α: es la aceleración angular=?

θ: es el desplazamiento o número de vueltas = 120 rev = 754,0 rad

Las conversiones de unidades se hicieron sabiendo que 1 revolución = 2π radianes y que 1 minuto = 60 segundos.  

Resolviendo la ecuación (1) para α, tenemos:

\alpha = \frac{\omega_{f}^{2} - \omega_{0}^{2}}{2\theta} = \frac{(209,4 rad/s)^{2} - (377,0 rad/s)^{2}}{2*754,0 rad} = -65,2 rad/s^{2}  

Entonces, la aceleración angular es -65,2 rad/s². El signo negativo se debe a que el motor está desacelerando.  

b) El tiempo transcurrido se puede encontrar como sigue:

\omega_{f} = \omega_{0} + \alpha t

Resolviendo para t, tenemos:

t = \frac{\omega_{f} - \omega_{0}}{\alpha} = \frac{209,4 rad/s - 377,0 rad/s}{-65,3 rad/s^{2}} = 2,57 s

Por lo tanto, el tiempo transcurrido fue 2,57 s.

Espero que te sea de utilidad!

3 0
3 years ago
Which type or types of motion is particle motion in surface waves?
kipiarov [429]

Answer:

circular motion

In surface waves, particles of the medium undergo a circular motion. They are neither longitudinal nor transverse, for in longitudinal and transverse waves, all the particles in the entire bulk of the medium move in a parallel and a perpendicular direction, respectively, relative to the direction of energy transport.

Explanation:

Hope this helps

4 0
3 years ago
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