Answer:
He should stand from the center of laser pointed on the wall at 1.3 m.
Explanation:
Given that,
Wave length = 650 nm
Distance =10 m
Double slit separation d = 5 μm
We need to find the position of fringe
Using formula of distance



Put the value into the formula


Hence, He should stand from the center of laser pointed on the wall at 1.3 m.
Answer:
at load 13114.85 N beam fail
Explanation:
given data
radius r = 6.7 mm
load = 2710 N
distance = 41 mm
length = 19 mm
to find out
At what load we expect this specimen to fracture
solution
we will first flexural strength that is
flexural strength = load × distance / πr³
flexural strength = 2710 × 41 ×
/ π(6.7 ×
)³
flexural strength = 117.592 MPa
we know that for cross section specimen
flexural strength = 3load × distance / 2bd²
put here these value
117.592 ×
N/m² = 3 load × 41 ×
/ ( 2 × (19×
)³)
load = 117.592 ×
× ( 2 × (19×
)³) / ( 3 × 41 ×
)
load = 13114.85 N
so at load 13114.85 N beam fail
Answer: constructive interference in which waves strengthen each other
Explanation:
Answer:
what is the question? there isn't one
Answer:
Em₀ = 245 J
Explanation:
We can solve this problem with the concepts of energy conservation, we assume that there is no friction with the air.
Initial energy the highest point
Em₀ = U
Em₀ = m g h
The height can be found with trigonometry
The length of the pendulum is L and the length for the angle of 60 ° is L ’, therefore the height from the lowest point is
h = L - L’
cos θ = L ’/ L
L ’= L cos θ
h = L (1 - cos θ)
We replace
Em₀ = m g L (1- cos θ)
Let's calculate
Em₀ = 10 9.8 5.0 (1 - cos 60)
Em₀ = 245 J