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Alisiya [41]
3 years ago
12

What is the name of this alkane?

Chemistry
2 answers:
asambeis [7]3 years ago
6 0
C.
The compound has a ring, so it has cyclo in the name.
Always use the smallest numbers to get to the "extensions" that is where the 3 comes from because the methyl attachment is off of the third bond in the ring.
nlexa [21]3 years ago
5 0
C...........................
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What is the molarity of a 3.0 solution of magnesium chloride prepared with 9.0 molecules of MgCl2 A. 6.0 M B. 3.0 M C. 27.0 M D.
Gala2k [10]

Answer:

Option B. 3.0 M

Explanation:

From the question given above, the following data were obtained:

Volume of solution = 3.0 L

Mole of MgCl₂ = 9 moles

Molarity =?

Molarity can simply be defined as the mole of solute per unit litre of the solution. Mathematically, it can be expressed as:

Molarity = mole of solute /Volume of solution

With the above formula, we can obtain the molarity of the solution as follow:

Volume of solution = 3.0 L

Mole of MgCl₂ = 9 moles

Molarity =?

Molarity = mole of solute /Volume of solution

Molarity = 9 / 3

Molarity = 3 mol/L = 3.0 M

Thus, the molarity of the solution is 3 M

8 0
3 years ago
A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol the molar mass of S
slamgirl [31]

The molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.

<h3>How to calculate molarity?</h3>

The molarity of a solution can be calculated using the following formula:

Molarity = no of moles/volume

According to this question, a solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water.

no.of moles of CuSO4 = 35g ÷ 159.6g/mol

no. of moles of CuSO4 = 0.22 moles

Therefore; molarity of CuSO4 solution is calculated as follows:

M = 0.22 ÷ 0.25

M = 0.88M

Therefore, the molarity of a solution that contains 35.00 g of CuSO4 dissolved in 250.0 mL of water is 0.88M.

Learn more about molarity at: brainly.com/question/12127540

6 0
2 years ago
At 25 °C, what is the hydroxide ion concentration, [OH−] , in an aqueous solution with a hydrogen ion concentration of [H+]=4.8×
algol [13]

[OH⁻]= 1 x 10⁻¹⁴ : 4.8 x 10⁻⁴ = 2.083 x 10⁻¹¹

3 0
2 years ago
An atom with 4 protons and 4 neutrons Is called?
Bas_tet [7]

Answer:

i'm pretty sure it's beryllium

Explanation:

5 0
3 years ago
Read 2 more answers
#1: The element that loses electrons in a chemical reaction is said to have been which of the following?
Mrrafil [7]
#1: The element that loses electrons in a chemical reaction is said to have been which of the following? A. reduced

B. oxidized

C. combusted

D. rusted

**idk, is it reduced or oxidized??

Answer: oxidized. The element that loses electrons increases its oxidation number (becomes more positve or less negative) and this is oxidation.


Which type of reaction occurs if one element gains electrons and another loses electrons?

A. combustion

B. synthesis

C. oxidation-reduction

D. double-displacement

**my answer: C

Yes, oxidation-reduction

#3: What is the oxidation number for phosphorus in H4P2O7?

A. +5

B. +3

C. +1

D. - 1

**my answer: A. +5

This is the way to calculate it 4(+1) + 2x + 7(-2) = 0 => x = +5



#4: What is the oxidation number for phosphorus in Na2HPO3?

A. +5

B. +3

C. +1

D. - 1

**my answer; B. +3

is that right??

Right

2(+1) + 1 + x + 3(-2) = 0 => x = 6 -1 -2 = 3 (positive)
5 0
4 years ago
Read 2 more answers
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