3 years ago

Is this right?????????????????????

Chemistry

1 answer:

aleksley [76]3 years ago

7 0

C and D are correct. This is the process of replication, and option E refers to repetition.

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Most genetic mutations are repaired by____

Kay [80]

The correct Anwser is enzymes

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3 years ago

if you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of

OverLord2011 [107]

Answer:

The mole fraction of codeine is 5.4%

Explanation:

Mole fraction = Mole of solute / Total moles (Mole solute + Mole solvent)

Solute (Codeine)

Molar mass 299.36 g/m

Mass / Molar mass = Mole → 46.85 g /299.36 g/m = 0.156 moles

Solvent (Ethanol)

Molar mass 46.07 g/m

125.5 g / 46.07 g/m = 2.724 moles

Mole fraction (Codeine) 0.156 / (0.156 + 2.724) → 0.054

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3 years ago

QUIZ 3: GOLDEN YEARS TO BOHR MODEL quizleConsider the two electron arrangements for neutral atoms A and B. What is the atomic nu

ELEN [110]

Answer:

Explanation:

trust me

5 0

2 years ago

A concentrated salt solution has a mass of 5.29 g for a 5.00 mL sample. What is the specific gravity of this solution

TiliK225 [7]

Answer:

$\rho_s=1.07g/cc^3$

Explanation:

From the question we are told that:

Mass $M=5.29g$

Volume $V=5.00mL=>5.0cc^3$

Generally the equation for Specific Gravity momentum is mathematically given by

$Specific\ Gravity\ g= Density\ of\ Salt\ Solution\ \rho_s / Density\ of\ Water\ \rho_w$

$g=\frac{ \rho_s} { \rho_w}$

$\rho_s=\frac{ g} { \rho_w}$

$\rho_s=\frac{ 5.29} { 5}$

$\rho_s=1.07g/cc^3$

7 0

3 years ago

The air bags in automobiles were once inflated by nitrogen gas generated by the rapid decomposition of

Basile [38]

Answer:

1.57 mol NaN₃

Explanation:

2 NaN₃ (s) → 2 Na (s) + 3 N₂ (g)

First we use PV=nRT to calculate the number of N₂ moles that need to be produced:

P = 1.07 atm

V = 53.4 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 23.7 °C ⇒ 23.7 + 273.16 = 296.86 K

Inputing the data:

1.07 atm * 53.4 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.86

And solving for n:

n = 2.35 mol N₂

Finally we convert N₂ moles into NaN₃ moles, using the stoichiometric coefficients of the balanced reaction:

2.35 mol N₂ * $\frac{2molNaN_3}{3molN_2}$ = 1.57 mol NaN₃

4 0

3 years ago