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Margaret [11]
3 years ago
5

Which of the temperatures below is most likely to be the boiling point of water at 880 torr?view available hint(s)which of the t

emperatures below is most likely to be the boiling point of water at 880 torr?92°c105°c100°c?
Chemistry
1 answer:
Luden [163]3 years ago
6 0
Boiling point<span>  is the </span>temperature<span> at which the vapor pressure of the liquid equals the surrounding pressure.

Above boiling point point, liquid get converted into vapour.

Now, boiling point of water is 100 oC at room pressure. Room pressure is equal to 760 torr. Thus, at 100 oC, vapour pressure of water becomes equal to 760 torr.

Now, if external pressure is increased to 880 torr, more heat is to be supplied so that vapour pressure of water equals 880 torr.

So, at 880 torr, boiling point of water will be more than 100 oC. In present case, most like the boiling point of water is equal to 105 oC.


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Metals lose electrons and become
antoniya [11.8K]

Ionic compounds are molecules that form through the gain and loss of electrons. A metal atom that loses an electron takes on a positive electric charge .

6 0
3 years ago
A mixture containing nitrogen, hydrogen, and iodine established the following equilibrium at 400 °C:2NH3(g) + 3I2(g) ⇌ N2(g) + 6
miss Akunina [59]

Answer: The value of K_{c} for this reaction is 250000.

Explanation:

The given equation is as follows.

2NH_{3}(g) + 3I_{2}(g) \rightleftharpoons N_{2}(g) + 6HI(g)

N_{2}(g) + 3H_{2}(g) \rightleftharpoons 2NH_{3}(g); K_{c_{1}} = 0.50   ... (1)

H_{2}(g) + I_{2}(g) \rightleftharpoons 2HI(g); K_{c_{2}} = 50  ... (2)

To balance the atoms, multiply equation (2) by 3. Hence, the equation (2) can be re-written as follows.

3H_{2}(g) + 3I_{2}(g) \rightleftharpoons 6HI(g); K_{c_{2}} = (50)^{3}  ... (3)

Now, subtract equation (1) from equation (3). So, the equation formed will be as follows.

3I_{2} - N_{2} \rightleftharpoons 6HI - 2NH_{3}

This equation can also be re-written as follows.

3I_{2} + 2NH_{3} \rightleftharpoons N_{2} + 6HI

This equation is similar to the equilibrium equation given to us.

Therefore, during this subtraction the equation constants get divided as follows.

K^{'}_{c} = \frac{K_{c_{2}}}{K_{c_{1}}}\\= \frac{(50)^{3}}{0.50}\\= 250000

Thus, we can conclude that the value of K_{c} for this reaction is 250000.

6 0
3 years ago
Please please please help
weqwewe [10]

Answer:

See explanation.

Explanation:

Hello!

In this case, since the main molecular reaction that is taken place in the beaker is:

AgNO_3(aq)+BaI_2(aq)\rightarrow AgI(s)+Ba(NO_3)_2(aq)

In such a way, we understand that one breaker contained silver nitrate and the other one barium iodide. Thus, the complete molecular equations turns out:

2AgNO_3(aq)+BaI_2(aq)\rightarrow 2AgI(s)+Ba(NO_3)_2(aq)

Now, for the complete ionic equation, we just ionize the aqueous species:

2Ag^++2NO_3^-+Ba^{2+}+2I^-\rightarrow 2AgI(s)+Ba^{2+}+2(NO_3)^-

Finally, for the net ionic equation we cancel out barium and nitrate ions as the spectator one because they are both sides on the equation:

2Ag^++2I^-\rightarrow 2AgI(s)

Best regards!

3 0
3 years ago
This is a type of element or substance that is not a metal.
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Non-metal elements are Noble gases,Halogens,nonmetals,semimetals(metalloids). ( and maybe other metals)
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Chemical bonds contain energy that can be released when they are broken. True False
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The answer ox Falseeeeeeee......
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