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Margaret [11]
3 years ago
5

Which of the temperatures below is most likely to be the boiling point of water at 880 torr?view available hint(s)which of the t

emperatures below is most likely to be the boiling point of water at 880 torr?92°c105°c100°c?
Chemistry
1 answer:
Luden [163]3 years ago
6 0
Boiling point<span>  is the </span>temperature<span> at which the vapor pressure of the liquid equals the surrounding pressure.

Above boiling point point, liquid get converted into vapour.

Now, boiling point of water is 100 oC at room pressure. Room pressure is equal to 760 torr. Thus, at 100 oC, vapour pressure of water becomes equal to 760 torr.

Now, if external pressure is increased to 880 torr, more heat is to be supplied so that vapour pressure of water equals 880 torr.

So, at 880 torr, boiling point of water will be more than 100 oC. In present case, most like the boiling point of water is equal to 105 oC.


</span>
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2 years ago
calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w
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(b) The normal boiling point of water (J·K−1·mol−1) is -109Jmole^-^1K^-^1

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Lets calculate

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      (\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p = -5_m(\beta )+5_m(\alpha ) =  -\frac{\Delta H}{T}

 \alpha ,\beta → phases

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 (\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p == -\frac{\Delta_fH}{T_f}

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           = -22Jmole^-^1k^-^1

(b) (\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}

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(c) \Delta\mu =\Delta\mu(l)-\Delta\mu(s) =-S_m\DeltaT

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\mu(l,-5°C)-\mu(s,-5°C)=-Sm\DeltaT [\mu(l,0

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