Here is the answer in comma-separated list.
(5, 10) , (10,15), (15, 20) (20, 25) (25, 300 (30, 35)
You need 5 dimes while having 10 or 25
a. Using point C as a center of rotation, rotate the figure 90 degrees counterclockwise. Then, translate the figure 4 units down.
Answer:
Yes, there is sufficient evidence to conclude that performance on the problem solving task is lowered by having onlookers.
Step-by-step explanation:
Null hypothesis: The performance on the problem solving task is lowered by having onlookers.
Alternate hypothesis: The performance on the problem solving task is not lowered by having onlookers.
Test statistic (t) = (sample mean - population mean) ÷ (sample sd/√n)
sample mean = 89.8
population mean = 89.1
sample sd = √sample variance = √84.6 = 9.198
n = 21
Degree of freedom = n-1 = 21-1 = 20
Assuming a 5% significance level
The test is a two-tailed test. Critical values corresponding to 20 degrees of freedom and 5% significance level are -2.086 and 2.086
Test statistic (t) = (89.8 - 89.1) ÷ (9.198/√21) = 0.7 ÷ 2.007 = 0.349
Conclusion:
Fail to reject the null hypothesis because the test statistic 0.349 falls within the region bounded by the critical values.
There is sufficient evidence to conclude that performance on the problem solving task is lowered by having onlookers.
