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dlinn [17]
3 years ago
9

Find the value of the underlined digit 584.2

Mathematics
2 answers:
S_A_V [24]3 years ago
8 0
Hvahhahhsgasyes you do
yaroslaw [1]3 years ago
5 0
Depends on where the underline is
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7. If the volume of a cylinder, where the height is 3 times the radius, is 247, find the surface area of the cylinder.
lakkis [162]

Answer:

3.87987×10^5

Step-by-step explanation:

surface area of the cylinder =2πrh+2πr²

=2*π*247*3+2*π*(247)²

=3.87987×10^5

7 0
3 years ago
What are the zeros of the quadratic function f(x) = 8x2 – 16x – 15?
marusya05 [52]

8x^2 - 16x - 15 = 0

x = [ -(-16) +/- sqrt((-16)^2 - 4*8*-15) / ] 2*8

= 2.696, -0.696

4 0
3 years ago
Read 2 more answers
Triangle XYZ has vertices X(0,3), Y(2,0) and Z(4,2). if yo reflect triangle XYZ across the line x=4, what will be the coordinate
Paha777 [63]

As X' is the reflected point of X(0,3) , so the x co ordinate of X' = 0+8 =8 and here y co ordinate remains same.

So, X'= (8,3)

Like that way, Y' is the reflected point of Y(2,0) and Z' is the reflected point of Z(4,2)

As the point Z is lying on the line x=4 and the reflection is also across that line, so both Z and Z' represent same point.

Y'= (2+4, 0) = (6, 0)

Z' = (4, 2)

3 0
3 years ago
A fair dice is rolled. Work out the probability of getting a prime number. Give your answer in its simplest form.
Debora [2.8K]

Answer:

prime number = 2,3,5

P( getting prime number ) = 3/6

= 1/2

4 0
3 years ago
A boat can travel at an average speed of 10 miles per hour in still water. Traveling with the current, it can travel 6 miles in
oksano4ka [1.4K]

Answer: The speed of the current is 2 miles per hour.

Step-by-step explanation:

We know that the speed of the boat is:

S = 10 mph.

When the boat travels with the current, the speed will be:

S = 10mph + x

where x = speed of the current.

When the boat travels against the current, the speed will be:

S = 10mph - x

Now, for a given amount of time T, when the boat travels with the current, it moves a distance of 6 miles.

Then we have the equation:

(10mph + x)*T = 6mi

And against the current, in the same time the boat moves 4 mi, then:

(10 mph - x)*T = 4mi

Then we have the system of equations:

(10mph + x)*T = 6mi

(10 mph - x)*T = 4mi

Now, we can take the quotient of these two equations and get:

((10mph + x)*T)/((10 mph - x)*T) = (6mi/4mi)

(10mph + x)/(10 mph - x) = 3/2

Now we can solve this for x.

(10mph + x) = (3/2)*(10 mph - x)

10mph + x = (3/2)*10mph - (3/2)*x

x + (3/2)*x = (3/2)*10mph - 10mph

(5/2)*x = (1/2)*10mph = 5mph

x = (2/5)*5mph = 2mph.

The speed of the current is 2 miles per hour.

6 0
3 years ago
Read 2 more answers
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