1. Area of the right angled ∆ = 1/2 × base × height
height = 16m
base = √20² – 16²
= √400 –256
= √144
= 12 m
Area of the unshaded portion
= 1/2 × base × height
= 1/2 × 12 × 16
= 96m²
2. Area of the rectangle = 300ft × 150ft
= 45000sq. ft
Area of the shaded portion = 100² + (1/2×b×h)
= 10000 + (1/2×120×150)
= 10000 + 9000
= 19000 sq. ft
Area of the unshaded part of the rectangle
= (45000 – 19000)sq. ft
= 26000 sq. ft
Answer:
US is parallel to RT, and UR is parallel to ST
ST is perpendicular to US and UR is perpendicular to RT
Basically anywhere that there's lines that make right angles are perpendicular to each other
I hope this helps
Step-by-step explanation:
Its in the wrist my boy man thing
9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
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We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
I believe that is gonna be the 225 package.
Thats the lowest number that both 25 and 9 go into
