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Phantasy [73]
3 years ago
10

What is the percent of change from $315.00 to $220.00? round answers to the nearest percent?

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
8 0
Ths would be (220 - 315 )* 100
                       -------------
                             315

                =  -  30 %  to nearest percent
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How much water can this container hold?
kirill [66]

Answer: 24429.02

Step-by-step explanation:

4 0
3 years ago
A scuba diver is swimming 15 feet below the water’s surface. The diver swims up slowly at 0.5 feet per second for 4 seconds; and
STatiana [176]
0.5 x 4 = 2 feet / 2 feet in 4 seconds
15 - 2 = 13
New depth: 13 feet

0.4 x 3 = 1.2 feet / 1.2 feet in 3 seconds
13 - 1.2 = 11.8
New depth: 11.8 feet

8 0
3 years ago
Read 2 more answers
Please help and thank you!
Stolb23 [73]

The conversion is

x =  r \cos \theta

y = r \sin \theta

So

\dfrac y x = \tan \theta

We're given the fairly unusual

\theta = -\frac 5 2

It's fairly unusual because usually an angle is given in degrees or radians, and typically the radians are a fraction times pi. We'll assume radians.

\dfrac y x = \tan \theta = \tan(-5/2) \approx 0.747

Ah, there's our .75. The approximate answer is

y = 0.75 x

Third choice.

The exact answer is

y = x \tan( -\frac 5 2)

also a line through the origin.

3 0
3 years ago
Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method
antoniya [11.8K]

Answer:

a

The estimate is  - 0.0265\le  K \le  0.0465

b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is  n_1 = 400

The number of faulty breaks of method A is  X_1 = 32

 The number of microchips broken in method B is  n_2  = 400

 The number of faulty breaks of method A is  X_2 = 32

  The proportion of the faulty breaks to the total breaks in method A is

       p_1 = \frac{32}{400}

      p_1 = 0.08

 The proportion of the faulty to the total breaks in method B is

      p_2 =  \frac{28}{400}

     p_2 =  0.07

For this estimation the standard error is  

      SE =  \sqrt{ \frac{p_1 (1 - p_1)}{n_1}  + \frac{p_2 (1- p_2 )}{n_2} } }

  substituting values

       SE =  \sqrt{ \frac{0.08 (1 - 0.08)}{400}  + \frac{0.07 (1- 0.07 )}{400} } }

      SE = 0.0186

The z-values of confidence coefficient of 0.95 from the z-table is  

       z_{0.95} =  1.96

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

        K = [p_1 - p_2 ] \pm z_{0.95} * SE

substituting values

        K = [0.08 - 0.07 ] \pm 1.96 *0.0186

         K  =  - 0.0265 \ or  \ K  =  0.0465

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is  

      - 0.0265\le  K \le  0.0465

3 0
3 years ago
Leda is ten years older than Pat. Write an algebraic expression that models Leda’s age with respect to Pat’s age.
iogann1982 [59]

Answer:

  • l = p + 10

Step-by-step explanation:

Let Leda's age is l and Pat's age is p.

<u>The expression would be:</u>

  • l = p + 10
7 0
2 years ago
Read 2 more answers
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