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storchak [24]
2 years ago
9

Find y-intercept for y= (x+2)(x-5)

Mathematics
1 answer:
Genrish500 [490]2 years ago
6 0

Answer:

y = -10

Step-by-step explanation:

To find the y-intercept, substitute x=0.

y= (0+2)(0-5)

Then, solve the equation for y.

y = -10

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If the discriminant of a quadratic equation is equal to -8, which statement describes the roots?
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Keywords

quadratic equation, discriminant, complex roots, real roots

we know that

The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form  ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}

where

The <u>discriminant</u> of the <u>quadratic equation</u>  is equal to

b^{2}-4ac

if  (b^{2}-4ac)> 0 ----> the <u>quadratic equation</u> has two <u>real roots</u>

if  (b^{2}-4ac)=0 ----> the <u>quadratic equation</u> has one <u>real root</u>

if  (b^{2}-4ac)< 0 ----> the <u>quadratic equation</u> has two <u>complex roots</u>

in this problem we have that

the <u>discriminant</u> is equal to -8

so

the <u>quadratic equation</u> has two <u>complex roots</u>

therefore

the answer is the option A

There are two complex roots

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