Answer:
ASA
Step-by-step explanation:
You can show the angles at either end of segment BC in triangles MBC and LCB are congruent, so you have two angles and the segment between. The appropriate theorem in such a case is ASA.
Answer: x = -5 and y = -5
Step-by-step explanation:
They drew the linear graph for the simultaneous equations on the graph already
The answer the the equations is the intersection of the lines which is (-5,-5) or x = -5 and y = -5
No because it is equal to -7.5 I think
Answer:
- a = 36°
- b = 36°
- c = 72°
- d = 72°
- e = 108°
- f = 16°
- g = 74°
- h = 70°
Step-by-step explanation:
You are expected to know and make use of the following relations:
- vertical angles are congruent
- angles of a linear pair are supplementary
- angles of a triangle sum to 180°
- alternate interior angles are congruent (at parallel lines)
- corresponding angles are congruent (at parallel lines)
- acute angles of a right triangle are complementary
- base angles of an isosceles triangle are congruent
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For this problem, it isn't always easiest to work the questions in order. It is best to start with the angles easiest to find from those given.
b and 144° are a linear pair, so b = 180° -144° = 36°
a and b are alternate interior angles, so a = b = 36°
2d and 144° are corresponding angles, so d = 144°/2 = 72°
e is the apex angle of an isosceles triangle with base angles 36°, so is 180° -2(36°) = 108° = e
f and 164° are a linear pair, so f = 180° -164° = 16°
g and f are complementary, so g = 90° -16° = 74°
g+h is a vertical angle with 144°, so is congruent to that. h = 144° -74° = 70°
c is the base angle of an isosceles triangle with b as the vertex angle. That means c = (180° -36°)/2 = 72°
The answer is 47.18181818
