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Aleksandr-060686 [28]
2 years ago
13

Why does heat flows from hot body to cold body?

Physics
1 answer:
deff fn [24]2 years ago
4 0

Answer:

<em>The atoms in the hot bodies have higher kinetic energy than those of the cold bodies. Thus to maintain thermal equilibrium, the atoms of higher kinetic energy tries to move and collide with the atoms of low kinetic energy. Thus heat transfers from a hot body to a cold body.</em>

<em>Explanation:</em>

<em>Explanation:The atoms in the hot bodies have higher kinetic energy than those of the cold bodies. Thus to maintain thermaler kinetic energy tries to move and collide with the atoms of low kinetic energy. Thus heat transfers from a hot body to a cold body. </em>

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The pumping of air into and out of the lungs in known as
sineoko [7]

Answer:

Respiration

Explanation:

The lungs and respiratory system allow us to breathe. They bring oxygen into our bodies (called inspiration, or inhalation) and send carbon dioxide out (called expiration, or exhalation). This exchange of oxygen and carbon dioxide is called respiration.

8 0
3 years ago
Sam is conducting an experiment in a closed room. He places two sound-generating instruments, A and B, in different places in th
diamong [38]

Answer: The correct answer is "Instrument A is placed closer to Sam than instrument B".

Explanation:

The sound can be soft or loud. Loudness depends on the amplitude of the sound wave. Higher the amplitude, more will be loudness. Lower the amplitude, lesser will be loudness.

Pitch depends on the frequency.

In the given problem, the instruments A and B generate sound waves of the same amplitude and at the same time.

Loudness depends on the sound energy produced as the energy of the sound is directly proportional to the square of the amplitude. It also depends on the distance between the source and the receiver.

Sam records a louder sound from instrument A than from instrument B. It means that there is mismatch in loudness. It can happen due to the placement of the instrument A closer to Sam than instrument B.

Therefore, the correct option is "Instrument A is placed closer to Sam than instrument B".

4 0
4 years ago
A vehicle moving with a uniform acceleration of 2 m/s2 has
Dahasolnce [82]

Answer:

a) 6 m/s

b) 14 m/s

Explanation:

Acceleration is change in velocity over change in time.

a) a = Δv / Δt

2 m/s² = (v − 4 m/s) / 1 s

v = 6 m/s

b) a = Δv / Δt

2 m/s² = (v − 4 m/s) / 5 s

v = 14 m/s

6 0
3 years ago
When a spinning star shrinks in radius, it speeds up. Which of the following statements explains this phenomenon?
Sever21 [200]

Answer:

B.)Angular momentum is always conserved

Explanation:

Angular momentum is given by:

L=mvr

where

m is the mass of the object

v is its speed

r is the distance between the object and the centre of its circular trajectory

In absence of external torques, angular momentum is always conserved. That means that for the spinning star, if its radius r decreases (because it shrinks), in order for L (the angular momentum) to be conserved, the speed (v) must increases, therefore the spinning star speeds up.

So, the correct choice is

B.)Angular momentum is always conserved

4 0
3 years ago
A boy walks a distance of 100 meters to the right at a steady speed of 1.00 m/s. Then he stops for 30 seconds. Then returns back
Mamont248 [21]

Explanation:

speed=\frac{Distance}{time}

In the figure attached:

A boy travels AB distance of 100 m, with speed of 1.00 m/s

AB = 100 m

1.00 m/s=\frac{100 m}{t_1}

t_1=100 s

After reaching at point B he stops there at for 30 seconds.

t_2= 30 s

After , 30 seconds he he comes back to his initial position that is A with steady speed of 1.00 m/s.

Distance covered from B to A= 100 m

Time taken by him during coming back=t_3

1.00=\frac{100 m}{t_3}

t_3=100 s

After returning to to point A he turns left and moves towards point C with speed of 1.5 m/s for 2 minutes.

Distance of AC = ?

t_4=2 min= 120 s

1.5 m/s=\frac{AC}{120 s}

AC = 180 m

The total time of his round trip is:T

T=t_1+t_2+t_3+t_4=100 s+30 s(stop)+ 100 s(returning)+120 s=350 s

The total distance: D

D = AB + BA (returning) + AC=100 m + 100 m + 180 m = 380 m[/tex]

The total displacement of boy:

Displacement is the shortest distance between the initial point and final point.

He first walked to point B from A and then came back to A . And after that walking to point C from A.So, the final displacement (d) is from A to C.

d = AC = 180 m

The total displacement of boy is 180 m.

The average speed of the boy is given by:

=\frac{AB+BA+AC}{t_1+t_2+t_3+t_4}=\frac{D}{T}

\frac{D}{T}=\frac{380 m}{350 s}=1.085 m/s

The average velocity of the boy is given by:

=\frac{AC}{t_1+t_2+t_3+t_4}=\frac{d}{T}

\frac{d}{T}=\frac{180 m}{350 s}=0.5142 m/s

5 0
4 years ago
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