Answer:
84 cups of water will leak out after 2 weeks
Step-by-step explanation:
* Lets how many how to change oz to cup
- One cup contains 8 oz
- We can use the ratio to solve this problem
- A hose is leaking water at a rate of 2 oz/h
- We need to find how many cups of water will leak out after 2 weeks
∵ The rate of the water leak out is 2 oz/hr
∵ 1 cup contains 8 oz
∴ 1 oz = 
cup
∴ 2 oz = 2 × = 
= 
cup
∴ The rate of the water leak out = cup/h
∵ 1 day = 24 hours
∵ 1 week = 7 days
∴ 1 week = 7 × 24 = 168 hours
∵ The number of hours in 1 week is 168
∴ The number of hours in 2 weeks = 168 × 2 = 336 hours
⇒ cups : hours
⇒ : 1
⇒ x : 336
- By using cross multiplication
∴ x = 336 ×
∴ x = 84
- x represents the number of cups of water leak out
<em>84 cups of water will leak out after 2 weeks</em>
Answer:
y=3
Step-by-step explanation:
(i used point-slope form which is (y1-y2)=m(x1-x2))
(10-y)=7(4-3)
10-y=7
-y=-3
y=3
Answer:
$ 6,500
Step-by-step explanation:
(52,000)(0.075)+(52,000)(0.05) = 3,900 + 2,600
= 6,500
Based on the information represented by the boxplot ;
- Latasha's lowest sale amount = 50
- Kayla's median is between 200 and 300
- Latasha has a greater spread due to higher IQR value
1.) <em><u>The Lowest amount of sale made by Latasha in one month </u></em>
- The minimum value is denoted by the starting position of the lower whisker on a boxplot.
- Lowest amount of sale made by Latasha = 50
2.) <em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>made</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>Kayla</u></em><em><u> </u></em><em><u>:</u></em>
- 50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.
- 50% of sales made by Kayla is between 200 and 300
- With median sale value being 250
3.) <em><u>Spread</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>middle</u></em><em><u> </u></em><em><u>50</u></em><em><u>%</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>sales</u></em><em><u> </u></em><em><u>:</u></em>
- The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution
- IQR = Upper Quartile (Q3) - Lower quartile(Q1)
<u>For Latasha</u> :
- Q3 = 450 (Endpoint of the box)
- Q1 = 150 (starting point of the box)
<u>For</u><u> </u><u>Kayla</u><u> </u><u>:</u><u> </u>
- Q3 = 375 (Endpoint of the box)
- Q1 = 100 (starting point of the box)
- IQR = 375 - 100 = 275
- Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.
Learn more :brainly.com/question/24582786
