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-BARSIC- [3]
2 years ago
15

C. What is oxidized in the reaction? What is reduced? (2 points)

Chemistry
1 answer:
Rina8888 [55]2 years ago
6 0

Answer:

Oxidation: a type of chemical reaction where one or more electrons are lost.

Oxidation State / Number: a number assigned to an atom describing its degree of oxidation, meaning how many electrons it has gained or lost.

Reduction: a type of chemical reaction where one or more electrons are gained.

Oxidation-Reduction Reaction: a chemical reaction where oxidation and reduction occurs simultaneously

Explanation:

Reduction always occurs at cathode

Oxidation always occurs in anode

These two process occurs in same way independent of nature of cell whether voltaic or electrolytic.

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What is always conserved in a chemical reaction?
Vaselesa [24]
The answer is b. Mass of the atoms

This is because of the law of conservation of mass. This means the mass in a system (in this case the reaction) can't change, so the quantity can't be added or removed
3 0
3 years ago
5.50 L of a 0.190 M CaCl2M CaCl2 solution<br> How do you find Grams?
Firdavs [7]

Answer:

115.891

Explanation:

Molarity is equal to moles/liters so to get moles we multiply molarity by liters, after this we multiply the moles by the total atomic weight of the compound to get grams

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2 years ago
What is the molar mass of chcl3?
svetlana [45]
Approximately 119.4 g, you take the mass on the periodic table of each element and add the numbers up
7 0
3 years ago
How many grams in a kilogram,how many quarts are in a pint and if how many ml of h20 = 1g
vodomira [7]

Answer:

1 g  +  10 g

Explanation:

5 0
3 years ago
Read 2 more answers
How much ch2o is needed to prepare 445 ml of a 2.65 m solution of ch2o?
worty [1.4K]

Answer: 35.4 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

Molality = 2.65

n= moles of solute =?

 V_s = volume of solution in ml = 445 ml

Putting in the values we get:

2.65=\frac{n\times 1000}{445ml}

n=1.18

Mass of solute in g=moles\times {\text {molar mass}}=1.18mol\times 30.02g/mol=35.4g

Thus 35.4 grams of CH_2O is needed to prepare 445 ml of a 2.65 m solution of CH_2O.

8 0
3 years ago
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