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Tom [10]
3 years ago
15

Two processes of plant reproduction are described below.

Chemistry
2 answers:
Stells [14]3 years ago
6 0

Answer:

Process 1 is pollination and Process 2 is germination

Explanation:

Pollination is the act of transferring pollen grains from the male anther of a flower to the female stigma. The goal of every living organism, including plants, is to create offspring for the next generation. One of the ways that plants can produce offspring is by making seeds.

Germination refers to the process by which an organism grows from a seed or a spore. The most common forms of germination include a seed sprouting to form a seedling and the formation of a sporeling from a spore. Thus, germination occurs primarily in plant and fungal species.

I hope this help :)

good luck

lesantik [10]3 years ago
3 0
1.

Pollination

2 germination
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3 years ago
I have to covert 4.4×10^4 Pa in to atm
Kitty [74]
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Sodium hydrogen carbonate NaHCO3, also known as sodium bicarbonate or "baking soda", can be used to relieve acid indigestion. Ac
olga2289 [7]

Answer:

1.4952 grams of sodium bicarbonate she  would need to ingest to neutralize this much HCl.

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

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Volume of hydrochloric acid solution = 200.0 mL = 0.200 L

Molarity of the hydrochloric acid = 0.089 M

n=0.089 M\times 0.200 L=0.0178 mol of HCL

HCl(aq)+NaHCO_3(aq)\rightarrow NaCl(aq)+H_2O(l)+CO_2(g)

According to reaction, 1 mole of HCl is neutralized by 1 mole of sodium bicarbonate.

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\frac{1}{1}\times 0.0178 mol=0.0178 mol of sodium bicarbonate

Mass of 0.0178 moles of sodium bicarbonate:

0.0178 mol × 72 g/mol = 1.4952 g

1.4952 grams of sodium bicarbonate she  would need to ingest to neutralize this much HCl.

8 0
3 years ago
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OverLord2011 [107]
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8 0
3 years ago
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If 11.9 kJ are used to heat a sample of water the temperature increases from 20.0°C to
Kipish [7]

Answer:

m=4.51g

Explanation:

Hello!

In this case, since the energy involved during a heating process is shown below:

Q=mCp\Delta T

Whereas the specific heat of water is 4.184 J/(g°C), we can compute the heated mass of water by the addition of 11.9 kJ (11900 J) of heat as shown below:

m=\frac{Q}{Cp\Delta T}

Thus, by plugging in, we obtain:

m=\frac{11900J}{4.184\frac{J}{g\°C}(650\°C-20.0\°C)}\\\\m=4.51g

Best regards!

7 0
3 years ago
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