The mass stays constant as a substance changes from a liquid to a gas.
The Law of Conservation of Mass states that, in ordinary chemical reactions, mass is neither destroyed nor created.
That is, the mass of the reactants must equal the mass of the products.
2H₂O(ℓ) ⟶ 2H₂O(g)
1 g 1 g
If the mass of liquid water is 1 g, the mass of the water vapour must be 1 g.
Even though the water vapour is a gas and you can’t see it, it still has a mass
of 1 g.
Answer:
the reaction is spontaneous at T > 2900 K
Explanation:
∴ ΔH = +120 KJ
∴ ΔS = (-42 J/K)*(KJ/1000 J) = -0.042 KJ/K
∴ ΔG < 0 ⇒ the reaction is spontaneous
⇒ at T = 2900 K:
⇒ ΔG = 120 - (2900)(-0.042) = 120 - 121.8 = - 1.8 KJ < 0
Answer:
the heat is circulating in the same spot rather than airing out into the open
Explanation:
Her you go hope this answers your question
Bond Order = [Σ (bonding e-) - Σ (antibonding e-)]/2
<span>Be2 = 4e = σ1(2e) σ2*(2e) σ3(0) π1(0) π2*(0) σ4*(0) bo = 0 </span>
<span>[Be2]+ = 3e = σ1(2e) σ2*(1e) σ3(0) π1(0) π2*(0) σ4*(0) bo = 0.5 </span>
<span>[Be2]+ would be more likely to exist since it has a bond order of 0.5 whereas Be2 has zero bond order</span>