Find the speed of a satellite in geostationary orbit.
1 answer:
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Answer:
2.8 N
Explanation:
Fp = 7.7 N
mA = 12.1 kg
mB = 7 kg
Let a be the acceleration and Fc be the contact force between A and B.
By the free body diagram, use Newton's second law
Fp - Fc = mA x a ..... (1)
Fc = mB x a ..... (2)
Adding both the equations
Fp = (mA + mB) x a
7.7 = (12.1 + 7) x a
a = 0.4 m/s^2
Substitute this value in equation (2), we get
Fc = 7 x 0.4 = 2.8 N
Thus, the contact force between the two blocks is 2.8 N.
Explanation:
