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2 years ago

Find the speed of a satellite in geostationary orbit.

Physics

1 answer:

mixas84 [53]2 years ago

4 0

Answer:

A geostationary orbit can be achieved only at an altitude very close to 35,786 kilometres (22,236 miles) and directly above the equator. This equates to an orbital speed of 3.07 kilometres per second (1.91 miles per second) and an orbital period of 1,436 minutes, one sidereal day

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What statement best illustrates vibrational motion?

kramer

C. a cello playing music at the concert

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3 years ago

Read 2 more answers

Explain why water boiling in a container stops<br>boiling momentarily when the lid is removed

Dmitriy789 [7]

Answer:

It's because it tips over the threshold from nucleate boiling, which we can see, to convection boiling, which we can't. ... Even if the steam stayed in the pot, it would still stop boiling when you removed the heat. The steam and water in a liquid/vapour mixture are at the same temperature (100ºC).

Explanation:

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3 years ago

A 98-kg fullback, running at 5.0 m/s, attempts to dive directly across the goal line for a touchdown. Just as he reaches the lin

Troyanec [42]

Answer:

(a) Explained below

(b) $v_f=0.35\ m/s$

Explanation:

<u>Law Of Conservation Of Linear Momentum</u>

The total linear momentum of a system of particles or objects is conserved unless an external force is acting on the system. The formula for the momentum of a body with mass m and velocity v is P=mv. If there is a system of bodies, then the total linear momentum is the sum of the individual momentums

$P=m_1v_1+m_2v_2+...+m_nv_n$

When objects collide and join together, the only final mass is the sum of all masses, all traveling at the same speed.

Our $m_1=98\ kg$ fullback runs at $v_1=5\ m/s$ . Two two 68-kg linebackers attempt to stop him, one at -2.0 m/s and the other at -4.0 m/s. The negative value is because the run against the positive direction, taken in the direction of the fullback.

(a) Before the event, there is a total linear momentum, computed as the sum of the momentums of each player as shown

$p_1=m_1v_1=(98)(5)=490 Kg\ m/s$

$p_2=m_2v_2=(68)(-4)=-272 kg\ m/s$

$p_3=m_3v_3=(68)(-2)=-136 kg\ m/s$

$p_t=p_1+p_2+p_3=390-272-136=82\ kg\ m/s$

After the collision, all the players keep joined in one single mass of.

$m_t=98+68+68=234\ kg$

They will move at a speed which will be computed below

(b) The final momentum of the system is

$p_f=m_tv_f=82\ kg\ m/s$

Since the linear momentum is conserved, the final speed $v_f$ is common to all of the players. Let's solve to find it

$\displaystyle v_f=\frac{p_f}{m_t}$

$\displaystyle v_f=\frac{82}{234}$

$v_f=0.35\ m/s$

(c) Since the final speed of the players is positive, it means the touchdown was actually scored, the fullback moved forward across the goal line, the positive reference.

5 0

3 years ago

A box is pulled 6 meters across the ground at a constant velocity by a horizontally applied force of 50 newtons. At the same tim

Vikentia [17]

Answer:

(a) Friction force = 50 N

(b) Work done by friction = 300 j

Explanation:

We have given that the box is pulled by 6 meter so d = 6 m

Force applied on the box F = 60 N

We have have given that velocity is constant so acceleration will be zero

So to applied force will be utilized in balancing the friction force