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2 years ago

10

Find the speed of a satellite in geostationary orbit.

1 answer:

mixas84 [53]2 years ago

4 0

Answer:

A geostationary orbit can be achieved only at an altitude very close to 35,786 kilometres (22,236 miles) and directly above the equator. This equates to an orbital speed of 3.07 kilometres per second (1.91 miles per second) and an orbital period of 1,436 minutes, one sidereal day

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How does a turbine produce energy

Ira Lisetskai [31]

A wind turbine turns wind energy into electricity using the aerodynamic force

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3 years ago

A 60-W light bulb radiates electromagnetic waves uniformly in all directions. At a distance of 1.0 mm from the bulb, the light i

slega [8]

Answer:

The appropriate solution is:

(a) $\frac{1}{4}(I_o)$

(b) $\frac{1}{4} (u_o)$

(c) $\frac{1}{2}B_o$

Explanation:

According to the question, the value is:

Power of bulb,

= 60 W

Distance,

= 1.0 mm

Now,

(a)

⇒ $\frac{I}{I_o} =\frac{r_o_2}{r_2}$

On applying cross-multiplication, we get

⇒ $I=I_o\times \frac{1_2}{2^2}$

⇒ $=I_o\times \frac{1}{4}$

⇒ $=\frac{1}{4} (I_o)$

(b)

As we know,

⇒ $\frac{u}{u_o} =\frac{I}{I_o}$

By putting the values, we get

⇒ $u=\frac{1}{4}(u_o)$

(c)

⇒ $\frac{B^2}{B_o^2} =\frac{u}{u_o}$

$=\frac{I}{I_o}$

⇒ $B=B_o\times \sqrt{\frac{1}{4} }$

⇒ $=\frac{1}{2}(B_o)$

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3 years ago

If i want an thrilling job witch should i chose im stuck beetween,

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Answer:

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3 years ago

The pressure P (in kilopascals), volume V (in liters), and temperature T (in kelvins) of a mole of an ideal gas are related by t

stich3 [128]

Answer:

$\dfrac{dV}{dt} = -0.466 m^3/s$

Explanation:

given,

P (in kilo pascals), volume V (in liters), temperature T (in kelvins)

P V = 8.31 T

Rate of increase the temperature = 0.1 K/s

temperature = 285 K

Pressure = 18 kPa

increasing at the rate of 0.07 k Pa/s

Rate at which volume is changing = ?

$V = 8.31 \dfrac{T}{P}$

$\dfrac{dV}{dt} = 8.31 \dfrac{P\dfrac{dT}{dt}-T\dfrac{dP}{dt}}{P^2}$

$\dfrac{dV}{dt} = 8.31 \dfrac{18 \times 0.1-285\times 0.07}{18^2}$

$\dfrac{dV}{dt} = 8.31 \dfrac{-18.15}{324}$

$\dfrac{dV}{dt} = -0.466 m^3/s$

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3 years ago

Question 10(Multiple Choice Worth 2 points)

Svetach [21]

$P = mv$

P momentum
m mass
v velocity

3 0

3 years ago

Read 2 more answers