All categories

3 years ago

Help I need to know this answer!!

Physics

1 answer:

worty [1.4K]3 years ago

4 0

Answer:

R2T

Because they said 2 rye bread which is R and one slice of turkey which is T so it is R2T

You might be interested in

If 2.0×10^−4 C of charge passes a point in 2.0×10^−6 s , what is the rate of current flow?1.0×10^−10 A1.0×10^2 A4.0×10^−1 A4.0×1

Ipatiy [6.2K]

This problem is about the rate of the current. It's important to know that refers to the quotient between the electric charge and the time, that's the current rate.

$I=\frac{Q}{t}$

Where Q = 2.0×10^−4 C and t = 2.0×10^−6 s. Let's use these values to find I.

$\begin{gathered} I=\frac{2.0\times10^{-4}C}{2.0\times10^{-6}\sec } \\ I=1.0\times10^{-4-(-6)}A \\ I=1.0\times10^{-4+6}A \\ I=1.0\times10^2A \end{gathered}$

<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>

<em />

<h2>Therefore, the rate of the current flow is 1.0×10^2 A.</h2>

3 0

1 year ago

A charge of 6.7 × 10^-15 coulombs is located at a point where its potential energy is 5.6 × 10^-12 joules. What is the electric

natita [175]

Answer:

C. 8.4 × 10^2 volts

Explanation:

The potential energy of a charge is given by:

$U=qV$

where

q is the magnitude of the charge

V is the electric potential

In this problem, we have

$q=6.7\cdot 10^{-15} C$ is the charge

$U=5.6\cdot 10^{-12} J$ is the potential energy

Re-arranging the formula and using these numbers, we can find the electric potential:

$V=\frac{U}{q}=\frac{5.6\cdot 10^{-12} J}{6.7\cdot 10^{-15} C}=835.8 V = 8.4\cdot 10^2 V$

4 0

3 years ago

Read 2 more answers

Question 2 please help

Sergeeva-Olga [200]

Answer:

Explanation:

3 0

3 years ago

Why does the direction of the spin matter

Xelga [282]

Answer:

Is there like an image that comes with this because there's not enough information here.

Explanation:

8 0

3 years ago

Read 2 more answers

Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined t

luda_lava [24]

The horizontal distance traveled by the ball (range of motion) is given by the following equation:

$x= v_{0x} t$

In which $x$ is the range of motion, $v_{0x}$ is the horizontal component of the initial velocity, and $t$ is the time of motion.

First, lets calculate the horizontal component of the initial velocity:

$v_{0x}= v_{0}cos( \alpha)=13.9cos(35)=11.39$

Now, we calculate the time of motion from the equation that described the motion of the ball in the vertical axis:

$y= \frac{1}{2}at^2+ v_{0y}t$

In which $y$ is the position of the ball vertically, $v_{0y}$ is the vertical component of the initial velocity, $a$ is the acceleration in the vertical axis (which is gravity), and $t$ is time of motion.

We want to find the time when the ball lands, hence, when $y=0$ ; so the equation becomes:

$0= \frac{1}{2}at^2+ v_{0y}t=\frac{1}{2}at^2+ v_{0}sin( \alpha )t=\frac{1}{2}(-9.8)t^2+ 13.9sin(35 )t$

We rewrite it a bit more:

$-4.9t^2+7.97t=0$

This is a quadratic equation, so we use the quadratic equation formula to solve for time (we'll get two answers):

$t= -\frac{1}{9.8} [{-7.97}+-\sqrt{(7.97)^2}]$

Clearly, one of the answers is $t=0$ , this is before you kick the ball (it is on the ground), we want the nonzero answer (when it lands) so:

$t= -\frac{1}{9.8} ({-7.97}-7.97})=1.63$

Now, we plug-in the time value to the equation of the motion's range:

$x= v_{0x} t=(11.39)(1.63)=18.57$

The ball will travel 18.57 meters.

6 0

3 years ago

Read 2 more answers