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expeople1 [14]
3 years ago
9

Imagine a volcano erupting many times over a period of years. With following landforms is most likely to result of volcanic erup

tions: A valley, A mountain, or a canyon? Explain.
Science.
Physics
1 answer:
grigory [225]3 years ago
5 0
I would say mountain. As the volcanic lava and Ash builds up. The eventually forms a mountain. There are many volcanic mountains in the world, like mount. Everest.
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0.000236 kg has how many<br> significant figures?
SCORPION-xisa [38]

Answer:

6

Explanation:

everything after the decimal is counted

4 0
3 years ago
If 1.4% of the mass of a human body is calcium, how many kilograms of calcium are there in a 195-pound man?
Mamont248 [21]

Answer:

1.241 kg

Explanation:

The mass of the man in kg is 195 pound * (1/2.2) kg/pound = 195/2.2 = 88.64 kg

If 1.4% of the mass of a human body is calcium, then the mass of calcium inside the 88.64 kg man is

1.4% * 88.64 = 88.64*1.4/100 = 1.241 kg

So there's 1.241 kg of calcium inside a 195-pound man

8 0
4 years ago
Read 2 more answers
If you doubled the load resistor in a Wheatstone bridge, the load current would not be half as much. Why not?
Fofino [41]
Doubling the size of a load resistor increases the load current. Increasing the load resistance, in turn the total circuit resistance is reduced. The load current would not be half as much since when you increase the size of load resistor then load current increases.
6 0
3 years ago
The typical unit for a period used with Kepler's third law is
ollegr [7]
Well, if you're using the law to work with periods of Earth satellites,
then the most convenient unit is going to be 'hours' for the largest
orbits, or 'minutes' for the LEOs.

But if you're using it to work with periods of planets, asteroids, or
comets, then you'd be working in days or years.
6 0
3 years ago
The speed of the center of the earth as it orbits the sun is 107257 kmph and the absolute angular velocity of the earth about it
Sindrei [870]

Answer with Explanation:

We are given that

Speed ,v_0=107257 kmph

Angular velocity,\omega=7.292\times 10^{-5} rad/s

Radius of earth,r=6371 km=6371000 m

1 km=1000 m

Linear velocity,v=r\omega=6371000\times 7.292\times 10^{-5}=464.57 m/s

Linear velocity,v=464.57\times \frac{18}{5}=1672.46 km/h

Velocity at point A,v_A=-vi+v_0 j=-1672.46 i+107257j kmph

Velocity at point B,v_B=v_0j-vj=107257j-1672.46j=105584.54j kmph

Velocity at point C,v_C=v_0j+vi=1672.46 i+107257j kmph

Velocity at point  D,v_D=v_0j+vj=107257j+1672.46j=108929.46jkmph

3 0
3 years ago
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