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2 years ago

HELP I NEED THIS REALLY FAST WILL GIVE BRANILIEST!!!

Mathematics

2 answers:

krek1111 [17]2 years ago

8 0

The answer is B not A.

n200080 [17]2 years ago

6 0

the answer is A because it shows.

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Which equation is equivalent to 4s=t+2

Paraphin [41]

Answer:If we're solving for t my work is below:

t = 4 s - 2

If we're solving for s my work is below:

s = t + 2/4

Step-by-step explanation:

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3 years ago

A triangle is rotated 90° about the origin. Which rule describes the transformation?

Over [174]

Answer:

Step-by-step explanation:

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3 years ago

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A scale drawing of a building shows 1 inch = 8 feet. How many feet are represented by 3 ¾ inches on the drawing?

Gennadij [26K]

Answer:

30 feet is represented by 3 3/4 inches on the drawing

Step-by-step explanation:

We have the relation as;

1 inch = 8 feet

Thus;

3 3/4 inches = x feet

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6 0

3 years ago

Please help im so lost Ty btw

klasskru [66]

Answer:

1) gradient (00) (-2 4) = y2-y1 / 2-1 = 4/-2 = -2 m = -2/1 means = m = -2 (negative slope) 2) gradient y2-y1 / x2-x1 = 3-0 / 2-0 = 3/2 = (1 1/2)/1 m = 1 1/2 (positive slope) we use the formula y-values divided by the change in the x-values. The equation of the gradient each goes like this 1) y = -2x as y is at origin nothing else to add The equation of the gradient each goes like this 2) y = 1 1/2x The equation of the point formula 1) we take the y -y1 = m (x +x 1) = y-0 = -2x (x +0) (as m = -2) y = -2(x +0) and The equation of the point formula 2) y - 0 = m ( x +x1) y - 0 = 1 1/2( x +0) = y = 1 1/2( x +0)

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2 years ago

Find the derivative of ln(cosx²).

RoseWind [281]

Answer:

$\displaystyle \frac{dy}{dx} = -2x \tan (x^2)$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = \ln (\cos x^2)$

Step 2: Differentiate

Logarithmic Differentiation [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{(\cos x^2)'}{\cos x^2}$
Trigonometric Differentiation [Derivative Rule - Chain Rule]: $\displaystyle y' = \frac{-\sin x^2 (x^2)'}{\cos x^2}$
Basic Power Rule: $\displaystyle y' = \frac{-2x \sin x^2}{\cos x^2}$
Rewrite [Trigonometric Identities]: $\displaystyle y' = -2x \tan (x^2)$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

8 0

3 years ago