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Lubov Fominskaja [6]
3 years ago
9

What exactly is Aphelion Phenomenon? ​

Physics
2 answers:
Harman [31]3 years ago
7 0

What exactly is Aphelion Phenomenon?

<u>➪</u><u> </u><em>Aphelion</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>point</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>orbit</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>celestial</em><em> </em><em>body</em><em> </em><em>like</em><em> </em><em>planet</em><em>,</em><em> </em><em>comet</em><em> </em><em>or</em><em> </em><em>other</em><em> </em><em>body</em><em> </em><em>most</em><em> </em><em>distant</em><em> </em><em>from</em><em> </em><em>the</em><em> </em><em>sun</em><em>.</em>

<em> </em><em> </em><em>In</em><em> </em><em>simpler</em><em> </em><em>words</em><em>,</em><em> </em><em>When</em><em> </em><em>a</em><em> </em><em>celestial</em><em> </em><em>body</em><em> </em><em>is</em><em> </em><em>fathest</em><em> </em><em>from</em><em> </em><em>the</em><em> </em><em>sun</em><em> </em><em>this</em><em> </em><em>phenomena</em><em> </em><em>is</em><em> </em><em>known</em><em> </em><em>as</em><em> </em><em>Aphelion</em><em> </em><em>Phenomenon</em><em>.</em><em>.</em><em>.</em><em>.</em><em>~</em><em> </em>

<u>Example</u><u>:</u><u>-</u>

  • <u>When</u><u> </u><u>the</u><u> </u><u>Earth</u><u> </u><u>is</u><u> </u><u>at</u><u> </u><u>its</u><u> </u><u>aphelion</u><u> </u><u>point</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>4,800,000 km (3,000,000 miles) farther from the Sun</u><u>.</u><u> </u>
Westkost [7]3 years ago
3 0

Answer:

aphelion, in astronomy, the point in the orbit of a planet, comet, or other body most distant from the Sun. When Earth is at its aphelion in early July, it is about 4,800,000 km (3,000,000 miles) farther from the Sun

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The block in the drawing has dimensions L0×2L0×3L0,where L0 =0.5 m. The block has a thermal conductivity of 200 J/(s·m·C˚). In d
Dennis_Churaev [7]

Answer:

Q_p=18000\ J

Q_o=8000\ J

Q_g=72000\ J

Explanation:

Given:

  • Length of block, l=3L_o=3\times 0.5=1.5\ m
  • Breadth of block, b=L_o=0.5\ m
  • height of block, h=2L_o=2\times 0.5=1\ m
  • Thermal conductivity of the block, k=200\ W.m.^{\circ}C
  • Temperature on the hotter side, T_H=37^{\circ}C
  • temperature on the cooler side, T_L=7^{\circ}C
  • time for which the heat flows, t=4\ s

<u>REFER THE ATTACHED IMAGE FOR THE REFERENCE</u>

<em>The rate of heat flow using </em><em>Fourier's law</em><em> of conduction is given as:</em>

\frac{Q}{t}=k.A.\frac{dT}{dx}

<u>Now the amount heat flow perpendicular to the pink surface:</u>

\frac{Q_p}{4}=200\times (0.5\times 1.5).\frac{30}{1}

Q_p=18000\ J

<u>Now the amount heat flow perpendicular to the orange surface:</u>

\frac{Q_o}{4}=200\times (0.5\times 1).\frac{30}{1.5}

Q_o=8000\ J

<u>Now the amount heat flow perpendicular to the green surface:</u>

\frac{Q_g}{4}=200\times (1.5\times 1).\frac{30}{0.5}

Q_g=72000\ J

6 0
3 years ago
Bromium has two naturally occurring isotopes: 79br, with an atomic weight of 78.918 amu, and 81br, with an atomic weight of 80.9
saul85 [17]

The two different isotopes have weights :

w1 = 78.918 amu

w2 = 80.916 amu

average weight w3 = 79.903 amu

The mixing of two components can be modeled as

let the fraction of w1 be 'x'

hence w1. x + w2.(1-x)  = w3

now this is a linear equation in 'x'. Substituting the values we get

x = 0.507

hence the percentage of Br79 = 50.7% and the percentage of BR81 = 49.3%

8 0
3 years ago
A metal rod has a length of 123. cm at 200°C. At what temperature will the length be 92.6 cm if the coefficient of linear expans
mestny [16]

Answer:

\theta_{2} = 15400^0 C

Explanation:

The formula for linear expansivity, \alpha = \frac{l_{2} - l_{1}  }{l_{1} ( \theta_{2}  - \theta_{1} )}

original length, l₁ = 123 cm = 1.23 m

final length, l₁ = 92.6 cm =0.926 m

original temperature, θ₁ = 200°C

Linear expansivity, α = 2 * 10⁻⁵ °C⁻¹

Putting these values into the formula:

2 * 10^{-5}  = \frac{1.23 - 0.926  }{l_{1} ( \theta_{2}  -200 )}\\ \theta_{2}  -200 = \frac{0.304}{2 * 10^{-5} } \\\theta_{2} = 15200 + 200\\\theta_{2} = 15400^0 C

7 0
3 years ago
A person uses a surfboard to ride every 30th wave crest towards the beach. The wave crest travels at a speed of 1.6m/s and the d
pashok25 [27]

Answer:

8

Explanation:

Applying,

v = λf................ Equation 1

Where v = velocity/ speed of the wave, λ = wave length of the wave, f = number of waves the person surf in one seconds.

make f the subject of the equation

f = v/λ............ Equation 2

From the question,

Given: v = 1.6 m/s, λ = 24 m

Substitute these values into equation 2

f = 1.6/24

f = 0.0667 wave/seconds.

If,

in one seconds, the person surf a total wave crest of 0.0667

Therefore,

in one hours, he will surf a total wave crest of (0.0667×60×60) = 240 waves crest

He rides for every 30th wave crest,

Hence,

number of wave crest the person surf in one hour = 240/30 = 8

6 0
3 years ago
PLZ HURRY!!!
MAVERICK [17]

Answer:

7.8 miles just did it

Explanation:

4 0
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